Step 1) Identify the legs and the hypotenuse of the right triangle. | The legs have length '14' and 48 are the legs. The hypotenuse is X. See Picture | The hypotenuse is red in the diagram below: Steps 2 and 3 | Step 2) Substitute values into the formula (remember 'c' is the hypotenuse) | A2 + B2 = C2 142 + 482 = x2 | Step 3) Solve for the unknown | | Problem 2) Use the Pythagorean theorem to calculate the value of X. Round your answer to the nearest tenth.
Research the topic of Pythagorean triples and write a brief report on the subject. A "Pythagorean Triple" is a set of positive integers, a, b and c that fits the rule: a2 + b2 = c2 (Pierce, 2011). The Pythagorean Theorem is a theorem that relates the lengths of the three sides of any right triangle (Stapel, 2010). If the triangle had a right angle (90°) and you made a square on each of the three sides, then the biggest square had the exact same area as the other two squares put together (Pierce, 2011). The sides of the triangle that meet at the right angle are labeled as sides (a) and sides (b).
= Quine’s tabular: start with minterm, the smallest I Quine’s start = Iterated consensus: complete sum theorem 4.5.1 Iterated complete = Recursive: complete sum theorem 4.6.1 Recursive: complete ENEE 644 1 Quine-McCluskey Method Problem: Given a Boolean function f (may be Problem: (may incomplete), find a minimum cost SOP formula. cost # of literals Q-M Procedure: 1. 2. 2. 3.
Begin by writing the corresponding linear equations, and then use back-substitution to solve your variables. 10–1301–8001 159–1 x,y,z=( , , ) 10–1301–8001 159–1 = x-13z=15y-8z=9z=-1 = x-13(-1)=15y-8(-1)=9z=-1 = x=2y=1z=-1 x,y,z=(2 , 1 , -1) Determinants and Cramer’s Rule: 2. Find the determinant of the given matrix. 8–2–12 8–2–12 = 8*2 - (-1)(-2) = 16 - 2 = 14 3. Solve the given linear system using Cramer’s rule.
Problems Answer Grade Problem-1 a x+y=56 /3 b x+y=56 x+3x=56 56/4= 14 x=14 56-14=42 y=42 check 14+42=56 or 14+(14*3)=56 /3 c before we use elimination, we simplify the second equation by dividing by 25,000: new equation for b): 7x + 8y = 288 in order to eliminate a variable, multiply the first equation by -7: new equation for a): -7x + -7y = -266 Elimination: add the two equations and the x's cancel out: y = 22 x = 38-22 = 16 /3 d For the first equation, the intercepts are (56, 0) and (0,56). The intercept for the second equation is (0, 0). The lines would intersect at (14, 42) /3 Problem-2 a x+y=38 /3 b $175,000x+$200,000y=$7,200,000 /3 c Before we use elimination, we simplify the second equation
Name: Robert Christopher Date: 16/2/2011 ID: 0670000687 COMPARISON OF ARTERY AND VEIN Raw Data Table 1: Below are the results of the experiment completed through cutting down the vein and artery into a ring-like shape. A 10g-50g of mass is used to suspend the artery and vein; and measured it with a 1-meter ruler standing 90˚ on the table to distinguish how long it stretches with a specific mass weight. Average Length ± 0.05g/mm | Mass ± 0.05mm/g | Artery | Vein | | Trail 1 | Trial 2 | Average | Trial 1 | Trial 2 | Average | 0g | 393 | 377 | 385 | 370 | 374 | 372 | 10g | 392 | 376 | 384 | 368 | 372 | 370 | 20g | 391 | 375 | 383 | 366 | 370 | 368 | 30g | 390 | 374 | 382 | 364 | 368 | 366 | 40g | 389 | 373 | 381 | 362 | 366 | 364 | 50g | 388 | 372 | 38 | 360 | 364 | 362 | Data Presentation Table 2: Below are the results of the artery and vein’s length difference in mm. These results were known when the average results from the two trials were calculated. The results can be calculated with the following formula: "trial 1 + trial 2; then divide the result by 2 to get the average mean results”.
Write assignment statements that perform the following operations with the variables a, b, and c. a) Adds 2 to a and stores the result in b * b=a+2 b) Multiplier b times 4 and stores the result in a * a=b*4 c) Divides a by 3.14 and stores the result in b * b=a/3.14 d) Subtract 8 from b and stores the result in a * a=b-8 4. Assume the variables result, w, x, y, and z are all integers, and that w=5, x=4, y=8, and z=2. What value will be stored in result in each of the following statements? a) Set result = x + y * 12= x + y b) Set result = z + 2 * 4=z * 2 c) Set result = y / x * 2=y / x d) Set result =y – z * b=y – z 5. Write a pseudocode statement that declares the variable cost so it can hold real numbers.
The method used to convert the measurement in inches to a decimal was to take the recording of the number plus the fraction out of 8 and add it to the nearest tenth of the smallest division. For the Vernier Caliper, we recorded the reading by finding a mark on the sliding scale that lined up with any mark on the fixed scale. Then the lines that line up with the number on the fixed scale is recorded based on the intervals between two of the numbers. For the micrometer, the number of millimeters on the frame is first read. If the next mark is visible, we add 0.5 mm.
And C/Y and P/Y is set to 1. h. Whatever you need to solve, e.g. if you want to solve for I, take the cursor there, press ALPHA and then Press SOLVE. 3. To set the calculator for 4 decimal places. a.
Use Excel to collect the data. 3.0 Data and Graph First of all, we draw a table to collect the data. Time/(±0.01s) | Voltage/(±0.01V) | LN(Voltage) | 0 | 13.71 | 2.61812549 | 3 | 10.41 | 2.34276688 | 6 | 6.32 | 1.84371921 | 9 | 4.16 | 1.42551507 | 12 | 2.82 | 1.03673688 | 15 | 1.89 | 0.63657683 | 18 | 1.35 | 0.30010459 | 21 | 0.98 | -0.0202027 | 24 | 0.69 | -0.3710637 | 27 | 0.51 | -0.6733446 | 30 | 0.38 | -0.967584 | And then we draw a graph using those data above. The gradient of the line | -0.12202 | 2.573096 | The Y-intersect of the line | The error of the gradient | 0.002662 | 0.047249 | The error of the Y-intersect