Chapter 1 review questions 1. Which of the following is true about 1 bit? a. Can represent decimal values 0 through 9 b. Can be used to represent one character in the lowercase English alphabet c. Represents one binary digit d. Represents four binary digits 2.
Adding the two cases above, we arrive at the answer: un = un−1 + un−2 . (c): Use either (a) or (b) to determine the number of bit strings of length 7 that do not contain two consecutive zeros. SOLUTION: We note directly that u1 = 2 and u2 = 3. Then u3 = 2 + 3 = 5, u4 = 3 + 5 = 8, u5 = 5 + 8 = 13, u6 = 8 + 13 = 21, and u7 = 13 + 21 = 34. Problem 3.
When the module is called, it should display the product of its argument multiplied times 10. Module main() timesTen() Module timesTen Dim Result As Integer Set result = value * 10
Yes because the 190 falls under class b. Exercise 8.1.5 What is the slash notation equivalent of subnet mask 255.255.255.0? 11111111.11111111.11111111.00000000 What is the
Therefore, subtract the function “h” from “f”, and then input 4 for the x values. Since there are rules of composition, each function may be calculated separately and then subtracted. Simplifying the h function = h4=7-(4)3 Take the h function and replace the variable x with 4 within the expression. h4=1 3 (7-4) First, subtract -1 by 4 inside the parentheses. Then, subtract 4 from 7. h4=3 3 When subtracting 4 from 7 the answer is 3. h4=3 3 Cancel out the common factors of 3 from the expression.
Because when you plug the binary numbers into the 8 bit conversion table, the two zeros before the 10 equal nothing. So 10 and 0010 have the same decimal number. 128 64 32 16 8 4 2 1 128 64 32 16 8 4 2 1 1 0 = 2 0 0 1 0 = 2 3. Based on the breakdown of the binary and decimal systems in this lab, describe the available digit values and the first four digits of a base 5 numbering system. You can use the binary system as a reference, where the available digit values are 0 and 1 and the first four digits are 1, 2, 4, and 8.
7. Given 9 bits of mask for the host portion, how many host addresses are available? 8. Given 13 bits of mask for the host portion, how many host addresses are available? 9.
Give a complete explanation for the "Negative ..._______The negative exponent rule states that when a variable or number is raised to a negative exponent, the expression may be rewritten as one divided the variable or number raised to that positive exponent. A negative exponent indicates “reciprocal”. When a factor is moved from the denominator to the numerator or from the numerator to the denominator, the sign of the exponent changes.9. Give a complete explanation for the "Fraction raised to... ______In the fraction raised to a negative exponent rule, with fractions in the form a over b, a is not equal to zero and b is not equal to zero. A over B with a negative
5) Information about Clearwater Company's direct materials cost follows: Standard price per materials ounce $ 100 Actual quantity used 8,700 grams Standard quantity allowed for production 9,100 grams Price variance $ 76,125 F ________________________________________ Required: What was the actual purchase price per gram? (Round your answer to 2 decimal places. Omit the "$" sign in your response.) Actual purchase price $ 91.25 Total grade: 0.0×1/1 = 0% Feedback: Actual Costs = AP × 8,700 Actual Inputs at Standard Price = $100 × 8,700 =$870,000 Price Variance = $76,125 F 8,700 × AP = $870,000 – $76,125 AP = $91.25 ________________________________________ Question 3: Score
printf("i=%d\n",i); i= i* j * 2; //Integer multiplication. printf("i=%d\n",i); j= i / 10; //Integer division printf("j=%d\n",j); return 0; } Exercise 1.4 Write a program that demonstrates the use of the +,-,* and / operators for floating point numbers. Type the following program. Compile, link and run it. #include <stdio.h> int main(