Daniel Jones NT1210 Lab 1.1 Review 1. Convert the decimal value 127 into binary. Explain the process of conversion that you used. 127 | 127 | 63 | 31 | 15 | 7 | 3 | 1 | 128 | - 64 | - 32 | - 16 | - 8 | - 4 | - 2 | - 1 | | = 63 | = 31 | = 15 | = 7 | = 3 | = 1 | = 0 | 0 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | The answer is: 01111111 If the decimal number is less than the greatest power of 2 than you must put a 0 for that number than carry that same decimal number over to the right one decimal place. For example.
TOPIC 8 Chi-Square goodness-of-fit test Problem 12.1 Use a chi-square goodness-of-fit to determine whether the observed frequencies are distributed the same as the expected frequencies (α = .05) Category | fo | fe | 1 | 53 | 68 | 2 | 37 | 42 | 3 | 32 | 33 | 4 | 28 | 22 | 5 | 18 | 10 | 6 | 15 | 8 | Step 1 Ho: The observed frequencies are distributed the same as the expected frequencies Ha: The observed frequencies are not distributed the same as the expected frequencies Step 2 df = k – m – 1 Step 3 α = 0.05 x 2 0.05, 5df = 11.0705 Step 4 Reject Ho if x 2 > 11.0705 Category | fo | fe | | 1 | 53 | 68 | | 2 | 37 | 42 | | 3 | 32 | 33 | | 4 | 28 | 22 | | 5 | 18 | 10 | | 6 | 15 | 8
If they want to cut this by a factor of three to get it down to $4000, they need to multiply the sample size by 3^2=9, and get a sample size of 25×9= 225. Here is how we can calculate it more directly. We want ME = 4000, and we know ME = 2×SE. Therefore, SE = ME/2 =2000, and also, SE = SD/Square root of sample size. So, 2000 = 30000/Square root of sample size.
MAT 161 College Algebra Name___________________________________ Midterm Review MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. Factor the polynomial by grouping. 1) x2 + 7x + 4x + 28 A) (x - 7)(x - 4) 1) B) (x - 7)(x + 4) C) (x + 7)(x + 4) D) prime Find an equation for the line with the given properties. 2) Perpendicular to the line x = 6; containing the point (5, 2) A) x = 2 B) y = 2 C) y = 5 D) x = 5 2) List the intercepts for the graph of the equation.
Make a copy of the Pledges worksheet, and then rename the copied worksheet as Q9. In the Q9 worksheet: a) Sort the filtered data by fund name in ascending (A to Z) order. b) Convert the table to a range. (Hint: When you convert your table to a normal range, the filter arrows in each column will disappear.) c) Filter the data to display only records with an amount received greater than zero.
The same literal equation will be used, however we are solving for another variable. The adult's dose is 1000mg and the child’s dose is 600mg. I need to SOLVE for a. d = D(a + 1) The Cowling’s Rule formula 24 600 = 1000(a + 1) I SUBSTITUTE the values for D and d 24 Using the same formula we will now solve a conditional equation to discover the child’s age. 600(24) = 1000(a + 1)(24) Both sides are multiplied by 24 to eliminate denominator. 24 14400 = 1000(a + 1) Multiplication is carried out.
Ethics Assignment – 15% of Your Grade This assignment should be submitted to the appropriate eCollege dropbox (under Week 8). REQUIRED PAPER FORMAT: Times New Roman, 12 point font Double spaced, with 1 inch margins In this case, George Stein is faced with an ethical dilemma. 1. First, describe the ethical dilemma presented in this case. • Then list all of the reasons why you believe George might act unethically and remove the filters, allowing the maggots to remain in the mix.
PSYC 354 Review Test Exam 4 Click Link Below To Buy: http://hwcampus.com/shop/psyc-354-review-test-exam-4/ Attempt Score 97.5 points scored Instructions Time limit: 1 hour and 30 minutes 40 multiple¬choice questions Open¬book/open¬notes Results Displayed Submitted Answers Question 2.5 out of 2.5 points 1 Imagine that the confidence interval around a group's mean is [980, 1160], what is the mean? Question 2.5 out of 2.5 points 2 A negatively skewed distribution would most likely violate which assumption? Question 0 out of 2.5 points 3 A researcher conducts a
Assessment 01.03 Module One Quiz. 1. Splott and Fizzle were solving for 2x+4=-3x+14. Both of them made some errors like when 2x+4=-3x+14 what they should have done was change the sign from -3x to +3x and moved it to the other side with the 2x, put both variables together, which would have been (2x+3x) +4= (+3x where the –3x was which is canceled out) +14, when solved it would have been 5x+4=14, then you would do the opposite of +4 to -4 to its original (the variable number is on one side with the equal sign) and subtracted from the 14 so It would come out to 5x=14-4 you solve 5x=10, divide by 5, x=10 over 5 solve for x, it would be 2 2. The function I created would be f(x) = 6x+11 3.
Then finally I divide all 3 by 703 in order to isolate W. 128.8 < W < 166.7 So people with the height of 73 inches could have a longer than average life span if they weigh between 129 and 167 pounds. The next equation 23<703WH^2<25 I first multiply all 3 terms by H^2 in order to take our the denominator. 23H^2 < 703W < 25H^2 Then I divide all terms by 703 to isolate the W. 23H^2703<W< 25H^2703 After doing this it now becomes an equivalent inequality for me to solve the second weight. I now use my height squared to find the second weight interval. 23(5329)703<W< 25(5329)703 After I multiply I end up with 122567703<W< 133225703 Then I simply divide and end up with 174 < W < 189.5.