Nt2640 Assignment 1

1216 Words5 Pages
Erica Moskovitz NT2640 July 3, 2014 Homework 3 1) How many bits of mask are required to provide 30 host addresses? subnet address of 130.68.0.0 with a mask of 255.255.248.0 will give you 2046 useful addresses. These addresses will be within the 130.68.0.0-130.68.7.255 range. 2) How many networks will be created using 255.55.0.0 given class A IP network(ie 10.0.0)? The Class A networking address scheme is designed for the government and large institutions needing a great deal of unique nodes. Although the Class A network has only 254 unique network addresses, it can contain approximately 17 million unique nodes, which can make subnetting such a network a nightmare. Getting up to speed with subnetting Class A addresses requires a little forethought, some basic…show more content…
4 | 12 | 16 | 4,094 | 11111111.11111111.11110000.00000000255.255.240.0 | /20 | x.y.N*16.0 | 12) Explain the reasoning behind the concepts of “subnet zero”? Subnet Zero If a network address is subnetted, the first subnet obtained after subnetting the network address is called subnet zero. Consider a Class B address, 172.16.0.0. By default the Class B address 172.16.0.0 has 16 bits reserved for representing the host portion, thus allowing 65534 (216-2) valid host addresses. If network 172.16.0.0/16 is subnetted by borrowing three bits from the host portion, eight (23) subnets are obtained. The table below is an example showing the subnets obtained by subnetting the address 172.16.0.0, the resulting subnet mask, the corresponding broadcast addresses, and the range of valid host addresses. Subnet Address | Subnet Mask | Broadcast Address | Valid Host Range | 172.16.0.0 | 255.255.224.0 | 172.16.31.255 | 172.16.0.1 to 172.16.31.254 | 172.16.32.0 | 255.255.224.0 | 172.16.63.255 | 172.16.32.1 to 172.16.63.254

More about Nt2640 Assignment 1

Open Document