OPRE 6302 Task 1

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OPRE 6302: Homework Assignment 4 Problem 1: A)Make -to –order process flow diagram Task 2 Task 2 Task 1 Task 3 Task 4 Machine Task 6 Task 5 B) This process is operating “as early as possible”. B ecause the second Task4 operates immediately after the second Task2 completed, so there are some idle time between the second Task4 and the second Task5. C) Bottlenecks of the process Resource Alex Chloe& Bob Dorothy Machine Erin Activity time (in minutes) 2+3=5 12 5 5 3+3=6 Capacity (flow units per hour ) 1/5 x 60=12 2/12 x 60=10 1/5 x 60=12 1/5 x 60=12 1/6 x 60=10 • Both Chloe& Bob and Erin are bottlenecks, because their capacities are the lowest in all resources. D) Gannt Chart During minutes 39 There are 4 flow units in the process during minutes 39. Because according to the Gannt chart, there are 4 different colors during minutes 39.…show more content…
E) According to Little’s Law Average Inventory =Average Flow Rate x Average flow time According to Gannt Chart, every 5minutes one order • Demand rate=1/5 x 60 =12 flow units per hour, • Capacity of process =10 flow units per hour • Average flow rate =minimum of {demand rate, process capacity } =10 flow units per hour Average flow time Order Arrival(minutes) Departure(minutes) Flow time(minutes) 1 0 25 25 2 5 31 26 3 10 37 27 4 15 43 28 5 20 48 29 … … … … So, Average flow time= (25+24+n)/2=(49+n)/2 minutes, n =∞ • Average Inventory= 10 x ∞ =∞

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