Math 0960_WC M6 WPS Activity Page 1 of 2 | Using the attachment at the bottom of this page or using the textbox at the bottom of this page submit response to the following questions. Please write the questions out in a different color above your answers.Your text shows the rules for exponents on page 238. In this activity you will be asked to summarize SOME of these rules in words. (As if you were explaining them to someone over the phone.) I will start this activity by doing the first rule for you then you will write an explanation for the remaining 6 rules:1.
1. Factor a trinomial whose leading coefficient is 1. Pick any one of the problems and solve the trinomial. If the trinomial is prime, state this and explain why. a. x2+8x+15 b. x2–4x –5 c. x2–14x+45 2.
Associate Program Material Appendix K Currency Conversion Peer Review Design Inspection Report |Programmer’s Name: |Brandon | |Date of Inspection |4/1/2012 | |Inspector’s Name: |Brandon | Use the following criteria to evaluate the Currency Conversion Test Procedure. If the answer to the item question is yes, place an X next to that item under the Yes column. If the answer is no, add details next to that item under the Comments column. | |Yes |Item |Comments | | |X |Is the problem description clear, concise, and accurate? | | | |X |Are the inputs to the program identified?
due = downpayment – total 10. Write a pseudocode statement that multiplies the variable subtotal by 0.15 and assigns the result to the variable totalfee. First you must make the variables real numbers. example.Dim subtotal As Double = 0 The statement asked for in the question will appear as totalfee = subtotal *
We can conclude that the data are Poisson distributed. Chi-Square test of independence Problem 12.12 Use the following contingency table to determine whether variable 1 is independent of variable 2. Let α = .01 | Variable 2 | Variable1 | 24 | 13 | 47 | 58 | | 93 | 59 | 187 | 244 | Step 1 Ho: the two classifications are independent Ha: the two classifications are dependent Step 2 d.f = (r – 1) (c – 1) Step 3 α = 0.01 x 2 0.01, 3df = 11.3449 Step 4 Reject Ho if x 2 > 11.3449 | Variable 2 | Total | Variable1 | 24 (22.92) | 13 (14.10) | 47 (45.83) | 58 (59.15) | 142 | | 93 (94.08) | 59 (57.90) | 187 (188.17) | 244 (242.85) | 583
Problems Answer Grade Problem-1 a x+y=56 /3 b x+y=56 x+3x=56 56/4= 14 x=14 56-14=42 y=42 check 14+42=56 or 14+(14*3)=56 /3 c before we use elimination, we simplify the second equation by dividing by 25,000: new equation for b): 7x + 8y = 288 in order to eliminate a variable, multiply the first equation by -7: new equation for a): -7x + -7y = -266 Elimination: add the two equations and the x's cancel out: y = 22 x = 38-22 = 16 /3 d For the first equation, the intercepts are (56, 0) and (0,56). The intercept for the second equation is (0, 0). The lines would intersect at (14, 42) /3 Problem-2 a x+y=38 /3 b $175,000x+$200,000y=$7,200,000 /3 c Before we use elimination, we simplify the second equation
|Step |Description | |Step 1: Identify the problem |You have to figure out what it is that you are trying to figure out. | | |It’s important that you identify the problem before trying to solve | | |it. How do you supposed to solve a problem if you haven’t identify it | | |first. | |Step 2: Discover the causes of the problem |After you have identify the problem then you have to find out where | | |the problem come from. You have to find the roots of the problem so | | |that you can start at the bottom of it.
Assignment #2 1) Improve the result from problem 4 of the previous assignment by showing that for every e> 0, no matter how small, given n real numbers x1,...,xn where each xi is a real number in the interval [0, 1], there exists an algorithm that runs in linear time and that will output a permutation of the numbers, say y1, ...., yn, such that ∑ ni=2 |yi - yi-1| < 1 + e. (Hint: use buckets of size smaller than 1/n; you might also need the solution to problem 3 from the first assignment!) 2) To evaluate FFT(a0,a1,a2,a3,a4,a5,a6,a7) we apply recursively FFT and obtain FFT( a0,a2,a4,a6) and FFT(a1,a3,a5,a7). Proceeding further with recursion, we obtain FFT(a0,a4) and FFT(a2,a6) as well as FFT(a1,a5) and FFT(a3,a7). Thus, from bottom up, FFT(a0,a1,a2,a3,a4,a5,a6,a7)
Choose which variable you want to eliminate; the coefficients of the variables must be exact opposites. You will only use two equations at one time. Second add the two equations together to cancel out your variables. IF nothing cancels than you have to multiply one or both of your equations by a number that will create an equal. Then for the unused equation and any of the other two equations repeat steps above.
Complete the square in a quadratic expression to reveal the maximum or minimum value of the function it defines. (supporting) | * Ability to recognize key features of a quadratic model given in vertex form | The focus in this unit is on the symbolic manipulation. | c. Use the properties of exponents to transform expressions for exponential functions. For example the expression 1.15t can be rewritten as (1.151/12)12t ≈ 1.01212t to reveal the approximate equivalent monthly interest rate if the annual rate is 15%. (supporting) | * Ability to connect experience with properties of exponents from Unit 2 of this course to more complex expressions | In Algebra I, exponents are limited to integers.