1. The graph approximates the points: E(r) σ Minimum Variance Portfolio 10.89% 19.94% Tangency Portfolio 12.88% 23.34% 10. The reward-to-variability ratio of the optimal CAL (using the tangency portfolio) is: 11. a. The equation for the CAL using the tangency portfolio is: Setting E(rC) equal to 12% yields a standard deviation of: 20.56% b. The mean of the complete portfolio as a function of the proportion invested in the risky portfolio (y) is: E(rC) = (l - y)rf + yE(rP) = rf + y[E(rP) - rf] = 5.5 + y(12.88 - 5.5) Setting E(rC) = 12% ==> y = 0.8808 (88.08% in the risky portfolio) 1 - y = 0.1192 (11.92% in T-bills) From the composition of the optimal risky portfolio: Proportion of stocks in complete portfolio = 0.8808 × 0.6466 = 0.5695 Proportion of bonds in complete portfolio = 0.8808 × 0.3534 = 0.3113 12.
The case structure lets the value of a variable or an expression determine which path of execution the program will take. 4) Briefly describe how the AND operator works. The AND operator takes two Boolean expressions as operands and creates a compound Boolean expression that is True only when both sub-expressions are true. The following is an example of an If-Then statement that uses the AND operator: If temperature < 20 AND minutes > 12 Then Display “The temperature is in the danger zone.” End If 5) Briefly describe how the OR operator works. The OR operator takes two Boolean expressions as operands and creates a compound Boolean expression that is true when either of the sub-expressions is true.
EXERCISE 23 Questions to be Graded 1. What is the r value for the relationship between Hamstring strength index 60°/s and the Shuttle run test? Is this r value significant? Provide a rationale for your answer. r = -0.149, the r value is not significant since it’s associated p-value = 0.424 > 0.05 which is the level of significance.
Radicals Tips 1. Make sure that one of the two factors of the radicand (expression under the radical) is the largest perfect square: Example: Simplify 72 Correct 72 = 36 ∙ 2 = 62 Incorrect 72 = 9 ∙ 8 = 38 2. To be able to add or subtract radicals, the radicands must be the same. Example 1: Add 32 + 52 Answer: Since radicands are the same, (3 + 5)2 = 82 Example 2: Subtract 73 - 3 Answer: (7 – 1)3 = 63 Example 3: 318 - 52 (Must simplify first) 39 2 - 52 3 ∙ 3 ∙ 2 - 52 92 - 520 Answer: 42
What value is stored in uninitialized variables? * Some languages assign a default value as 0 to uninitialized variables. Algorithm Workbench Review Questions: 3-10 3. Write assignment statements that perform the following operations with the variables a, b, and c. * Adds 2 to a and stores the result in b * Set b= 2 +a * Multiplies b times 4 and stores the result in a * set a= b*4 * Divides a by 3.14 and stores the result in b * set b= 3.14/b * Subtracts 8 from b and stored the result in a * set a= b-8 4. Assume the variables result, w, x, y, and z are all integers, and that w = 5, x = 4, y = 8, and z = 2.
TOP: Find probabilities for binomial experiments. KEY: Probability | Binomial Experiments 31. ANS: D Identify the parameters of binomial distribution and calculate the probability of the given event using binomial expansion. |Feedback| A|This is the probability of clearing less than three hurdles.| B|The probability of clearing at least three hurdles, and not exactly three hurdles, is
Quiz 5 Question 1 2 out of 2 points | | | In a 0-1 integer programming problem involving a capital budgeting application (where xj = 1, if project j is selected, xj = 0, otherwise) the constraint x1 - x2 ≤ 0 implies that if project 2 is selected, project 1 can not be selected.Answer | | | | | Selected Answer: | False | Correct Answer: | False | | | | | Question 2 0 out of 2 points | | | Rounding non-integer solution values up to the nearest integer value will result in an infeasible solution to an integer linear programming problem. Answer | | | | | Selected Answer: | True | Correct Answer: | False | | | | | Question 3 2 out of 2 points | | | If we are solving a 0-1 integer programming problem with three decision variables, the constraint x1 + x2 + x3 ≤ 3 is a mutually exclusive constraint. Answer | | | | | Selected Answer: | False | Correct Answer: | False | | | | | Question 4 2 out of 2 points | | | In a problem involving capital budgeting applications, the 0-1 variables designate the acceptance or rejection of the different projects. Answer | | | | | Selected Answer: | True | Correct Answer: | True | | | | | Question 5 2 out of 2 points | | | A conditional constraint specifies the conditions under which variables are integers or real variables. Answer | | | | | Selected Answer: | False | Correct Answer: | False | | | | | Question 6 2 out of 2 points | | | If we are solving a 0-1 integer programming problem, the constraint x1 ≤ x2 is a conditional constraint.
Limiting Reactants Mini Lab Results: Data Table of Quantitative Observations: Test Tube Moles of NaI reacted Moles of Pb(NO3)2 Reacted Mass of Empty Tube Mass of Tube with PbI2 ppt. Mass of PbI2 ppt. 1 1.0 x10 -3 1.5 10 -4 7.58g 7.65g .07g 2 1.0 x10 -3 2.5 10 -4 8.33g 8.43g .10g 3 1.0 x10 -3 5.0 10 -4 8.19g 8.43g .24g 4 1.0 x10 -3 7.5 10 -4 6.72g 6.97g .25g 5 1.0 x10 -3 1.0 10 -3 8.98g 9.12g .23g Calculations: Moles of NaI reacted (for all tubes) Volume used/1 x 1L/1000mL x mol/1L 2.0mL/1 x 1L/1000mL x .5/1L = 1.0 x10-3 Moles Pb(NO3)2 Reacted Volume used/1 x 1L/1000mL x mol/1L Test Tube 1 .3mL/1 x 1L/1000mL x .5/1L = 1.5 x10-4 Test Tube 2 .5mL/1 x 1L/1000mL x .5/1L =2.5 x10-4 Test Tube 3 1.0mL/1
9.2 Q1 Determine (f+g)(4) when f(x)=x^2-3 and g(x)=-6/(x-2). A1 10 Q2 What is the domain of (f-g),where f(x)=√(x+1) and g(x)=2log⁡[-(x+1) ]? A2 {x∈R|-1≤x≤1} Q3 a) Is the sum of two even functions even,odd,or neither?Explain. b) Is the sum of two odd functions even,odd,or neither?Explain. c) Is the sum of an even function and an odd function even,odd,or neither?Explain.
TASK 1 A. Complete the attached “Simulation Template” to determine the following costs: 1. Average materials cost per unit The first thing I had to do was figure out the random numbers interval in order to figure out the material cost per unit. Materials Probability Cost Random Numbers Interval* 0.2 $ 33.00 0.00 < 0 .20 0.33 $ 35.00 0.21 < 0.53 0.37 $ 38.00 0.54< 0.90 0.1 $ 39.00 0.91 < 1 *The random number interval came from the probability which was provided in the simulation template. I first start with 0.00 less than the probability which is 0.20 then we start at 0.21 less than 0.53.