Determination Of a Solubility Product

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Determination of a Solubility Product Abstract: The purpose of this experiment was to determine the solubility product constant (Ksp) for a sparingly soluble compound, Ca(OH)2, in pure water and in a NaOH solution. To determine the solubility product constant a solution of Ca(OH)2, in pure water was titrated with HCl. The concentrations of OH- and Ca2+ were used to calculate the solubility product constant. Another solution, containing Ca(OH)2, in NaOH was also titrated. The concentrations of OH- and Ca2+ were used to calculate the solubility product constant. For the solution containing Ca(OH)2, in pure water the concentration of the OH- ion was 0.06M and the concentration of the Ca2+ ion was 0.03M. For the solution containing Ca(OH)2, in NaOH the concentration of the OH- ion was 0.056M and the concentration of the Ca2+ ion was 0.028M. The solubility product constant was determined to be 1.8x10-4 for the solution of Ca(OH)2, in pure water and the solubility product constant for the solution of Ca(OH)2, in NaOH was determined to be 8.8x10-5. The solubility of the solution containing Ca(OH)2 in NaOH had a smaller solubility of 4.15 g/L than the solution containing Ca(OH)2 in water, which had a solubility of 4.45 g/L. This experiment successfully showed the relationship between the concentration of the Ca2+ ions in solution. Introduction: Many ionic compounds are considered to be “insoluble” in water, but no compound 8placed in water. When the slightly soluble compound stops dissolving the ions in the solution and the undissolved solid are in equilibrium. [2] A saturated solution is one that holds as much dissolved solute as possible at a given temperature, therefore only a small amount of a slightly soluble ionic compound is needed to produce a saturated solution of that compound. [2] The solubility of a salt is the amount of the salt that

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