Part C: Density of an Irregular Shaped Solid 1) Obtain a sample of metal and determine the mass. 2) Fill a 100 mL or 50 mL graduated cylinder with water, recording its volume. 3) Using the water displacement method, determine the volume of the object. 4) Determine the density and percent error. Part D: Density of Methanol 1) Find the mass of an empty 10 mL graduated cylinder, and then fill approximately 9 mL of methanol and record volume.
After the calibration, select one of unknown blocks in the shelf. In this lab, block No.5 was chosen. Use caliper to measure the length of the block and diameter of the hole. Use micrometer to measure the height and the width of block. Finally, use scale to measure the mass of the block.
From your three trials, calculate the average volume of Na2S2O3 needed for the titration of 25.00mL of diluted bleach. 3. Use the average volume and the molarity of Na2S2O3 to determine the molarity of the diluted bleach. (Find moles of Na2S2O3, convert to moles of NaClO, and divide by volume of dilute bleach that was titrated in each trial to get M). 4.
The volume in cubic feet of a box can be expressed as V(x) = x 3 − 6x 2 + 8x, or as the product of three linear factors with integer coefficients. The width of the box is 2 – x. a. Factor the polynomial to find linear expressions for the height and the width. b. Graph the function. Find the x-intercepts.
Metal Name Mass of Metal Volume of water Initial temp. in calorimeter Initial temp. in beaker Final temp. of mixture Aluminum 34.720g 26.0mL 25.4°C 100.6°C 41.6°C Part II: Insert a complete data table, including appropriate significant figures and units, in the space below. Also include any observations that you made over the course of part II.
The solution was then drained into an Erlenmeyer flask and I recorded the weight of the flask before (W1) and after the solution (W2) and then subtract the weight of the flask with the solution from the weight of the flask alone in order to find the absolute mass of the solution (W3). I repeated these steps 2 times. In order to find the density (D) of the solution I took the mass of the solution (∆W) and divided it by volume of the solution in the buret. I then averaged the two densities and found that the average density for the egg to float is 1.05g/mL. | 1st | 2nd | | Buret volume: 24mL | Buret volume: 24.1mL | W2 | 141.87g | 141.83g | W1 | 115.18g | 116.15g | ∆W = W2 – W1 | 25.06g | 25.37g | D = ∆W/buret volume | 1.04g/mL | 1.06g/mL | Average Density = 1.04 + 1.06 / 2 = 1.05 | I repeated the same process for the Mohr pipet as I did for the Buret.
After that, dissolve the sample in 2 mL of deionized water and shake the test tube for 1 to 1 ½ minutes to dissolve the solid. Place another dry test tube in a 50mL beaker and weigh it. Find a bottle of barium iodide and record the name and molar mass. Then, weight out either anhydrous barium iodide or barium iodide dehydrate into this test tube and dissolve is it in 2 mL of deionized water. Pour the contents of one of the test tubes into the other and a reaction should occur and you should see a white precipitate of barium sulfate form.
4. Submerge the bag in the beaker and leave overnight. 5. Dry off the bag and then record its mass. After this write down the color of the bag and the beaker solutions and then test the bag and beaker solutions for the presence of glucose.
Find the area of the base for the rectangular prism pictured above. Multiply the area of the base times the height. Record the volume of the rectangular prism. PRACTICE: Find the volume for a rectangular prism with a height 6 cm, length 5 cm, and width 3 cm. Be sure to include the units in all of your answers.
Body Mass Index Jacob Shearer MAT221 Introduction to Algebra Instructor Pamela Clarke November 17, 2013 I am going to solve the following 4 formulas involving Body Mass Index starting with the first one. 17<703WH^2<22 This is the equivalent inequality where I substituted BMI with the formula. Then I replace the H^2 with my height in inches. 17<703W73^2<22 After factoring in my height to the second power I get 17<703W5329<22 Now I multiply all 3 terms by the denominator 17(5329) < 703W(5329)5329 <22(5329) and then get 90593 < W < 117238. Then finally I divide all 3 by 703 in order to isolate W. 128.8 < W < 166.7 So people with the height of 73 inches could have a longer than average life span if they weigh between 129 and 167 pounds.