Procedure: Part I: Rectangular Solid (Wooden Block) Mass: In order to find the mass of the rectangular solid utilize the balance.Document the mass by rounding to the closest 0.1 g in the data table underneath. Volume: Find out the length, width, and height of the rectangular solid by utilizing the metric ruler. Document these by rounding to the closest 0.01 cm. Utilize the formula for
5 .For part III, Average was needed to be found after Find the Mass/A of each all 5 disk. To do that Add all the values in Table 3 and divide them by 5. 6 .For Part III, Percent difference between the average value and the slope of the derivative diameter graph was found by doing this: ((slope of the derivative vs. diameter graph- average)/slope of derivative vs. diameter graph)*100 =67.9% VII. Analysis Questions/Answers 1. The Slope in Part I represents π 2.
On comparing this equation with standard equation of ellipse with centre (h,k) which is given by x-h2a2+y-k2b2=1 , we have , h = 3 and k = -5. Therefore, coordinates of centre of ellipse = (3, -5). b) Given equation of ellipse. On comparing this equation with standard equation of ellipse with major axis 2a and minor axis 2b which is given by x-h2a2+y-k2b2=1 , we have, a2=64=>a=8 And b2=100=>b=10 Therefore, length of major axis = 2a = 2*8 = 16. And length of minor axis = 2b = 2*10 = 20. c) From part a) and b), we have a = 8 and b = 10 and h=3,k=-5 So, c2=b2-a2=102-82=100-64=36 =>c=sqrt36= 6.
How does this compare to the individual values of Byte 1 and Byte 2? The decimal equivalent of the binary sequence is 6,633 which is the sum of the values of byte 1 and byte 2. Exercise 1.3.3 Given a device with a storage capacity of 120 MB, how many bytes can be stored on this device? Show your calculations. 120 MB x 1024 = 122,880 KB x 1024 = 125,829,120 bytes Exercise 1.3.4 Given a computer with a disk capacity of 16 GB and a word size of 32 bits, how many words can be stored on the disk?
1. Factor a trinomial whose leading coefficient is 1. Pick any one of the problems and solve the trinomial. If the trinomial is prime, state this and explain why. a. x2+8x+15 b. x2–4x –5 c. x2–14x+45 2.
What is the volume of object 1? ______ 14.0 cm3 _______________________ Note: While milliliters (mL) are used to measure liquid volumes, the equivalent unit cubic centimeters (cm3) are used for solids. Therefore, write the volume of object 1 in cm3. Drag object 1 into the Beaker of Liquid. Does it sink or float?
* Explain what a radian measure represents using the unit circle as a reference. Pie is represented by a real number constant and is the ratio of the circumference of a circle to its diameter. Its value is approximately 3.14159. Since the circumference of the unit circle is 2 Pie, it is implied that the radian measure of an angle of one revolution is also 2 Pie. So the radian is the measure of how close a degree is to a complete circle.
Assignment #2 1) Improve the result from problem 4 of the previous assignment by showing that for every e> 0, no matter how small, given n real numbers x1,...,xn where each xi is a real number in the interval [0, 1], there exists an algorithm that runs in linear time and that will output a permutation of the numbers, say y1, ...., yn, such that ∑ ni=2 |yi - yi-1| < 1 + e. (Hint: use buckets of size smaller than 1/n; you might also need the solution to problem 3 from the first assignment!) 2) To evaluate FFT(a0,a1,a2,a3,a4,a5,a6,a7) we apply recursively FFT and obtain FFT( a0,a2,a4,a6) and FFT(a1,a3,a5,a7). Proceeding further with recursion, we obtain FFT(a0,a4) and FFT(a2,a6) as well as FFT(a1,a5) and FFT(a3,a7). Thus, from bottom up, FFT(a0,a1,a2,a3,a4,a5,a6,a7)
After the calibration, select one of unknown blocks in the shelf. In this lab, block No.5 was chosen. Use caliper to measure the length of the block and diameter of the hole. Use micrometer to measure the height and the width of block. Finally, use scale to measure the mass of the block.
Huifeng, et al [6], using triangle facets from STL model to determine V-map of an irregular face. First, an irregular face is converted to a STL model as we see in Figure 1. Each triangular facet which is composed by three vertexes is a regular face with single normal-vector. The entire normal-vectors are then used to build V-map through intersection