935 Words4 Pages

Name:
6.03: Calorimetry
Data and Observations: Part I: Insert a complete data table, including appropriate significant figures and units, in the space below. Also include any observations that you made over the course of part I. (4 points) I observed that when the metal is placed inside the calorimeter, it transfers heat to the water making the water increase temperature while the metal will decrease temperature. I also noticed that the system was the metal and the surroundings is the water, this is because the water is taking in the heat from the metal making the water warm.
Metal Name Mass of Metal Volume of water Initial temp. in calorimeter Initial temp. in beaker Final temp. of mixture
Aluminum 34.720g 26.0mL 25.4°C 100.6°C 41.6°C
Part II: Insert a complete data table, including appropriate significant figures and units, in the space below. Also include any observations that you made over the course of part II. (4 points)
Unknown (A,B,C,D) Mass of Metal Volume of water Initial temp. in calorimeter Initial temp. in beaker Final temp. of mixture
Metal C 25.605g 24.6mL 25.2°C 100.5°C 28.7°C
Calculations: Show your work and write a short explanation with each calculation. Part I: 1. Calculate the energy change (q) of the surroundings (water). We can assume that the specific heat capacity of water is 4.18 J/ (g · °C), and the density of water is 1.00 g/mL. (4 points) q = m × c × Δt Given: q=? m = 34.720g c = 4.18 j/(g x °C) Δt = 41.6°C - 25.2°C = 16.4°C
q = (34.720g) (4.18 j/(g x °C) (16.4°C) q = 2380.13j You are trying to ﬁgure out the energy change of the water which is the surroundings in the lab. To do that you must take the mass of the metal, which for me was Aluminum, and multiply it by the heat capacity of the water, which was given, then multiply that by the change in temperature, which is the ﬁnal temperature of the mixture

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