increase See Table 3: Lung Capacities and Minute Ventilation See Graph: Comparison of Resting and Exercising Lung Capacities and Minute Ventilation DISCUSSION 1. Explain the change in ERV with exercise. TV increases with exercise so the ERV decreases too. 2. Explain the change in IRV with exercise.
LABORATORY REPORT Activity: Recruitment and Isotonic and Isometric Contractions Name: Carolyn Chrzastowski Instructor: Professor Waite Date: 07.19.2015 Predictions When the arm goes from resting to flexing, the amplitude and frequency of sEMG spikes will increase During flexion, the amplitude and frequency of sEMG spikes will ___ during extension. be greater than Recruitment of motor units will be greatest when the load is 20 pounds Materials and Methods Comparison of motor unit activation during muscle tone and concentric and eccentric isotonic contractions Dependent Variable amplitude and frequency of sEMG spikes Independent Variable muscle movement Controlled Variables total number of motor units
P1V1=P2V2 3. Explain how your experiment results further prove Boyle’s law. Answer: As the pressure increased, the volume of the gas decreased. When multiplying the pressure change with the volume change, the product was always the same. This further proved Boyle’s Law.
Did the tidal volume increase, decrease, or not change with exercise? increase 3. Did the expiratory reserve volume increase, decrease, or not change with exercise? decrease 4. Did the inspiratory reserve volume increase, decrease, or not change with exercise?
Question 7.74 a. Increase in pressure. As the volume decreases, the pressure increases. b. The same.
If the weight is pushed to one side, gravity will again try to pull it back to the lowest point. When it gets there, of course, it will have kinetic energy and continue to move past the equilibrium point. Once it passes the equilibrium, gravity will again try to pull it back to the lowest point and the whole process repeats itself periodically.” So what
Inverse Square Law Newton's law of gravity describes a force that decreases with the SQUARE of the distance. For every factor of 2 the distance increases, the gravitational attraction decreases by a factor of 2 × 2 = 4; for every factor of 3 increase in distance, the gravity decreases by a factor of 3 × 3 = 9 (not by 3 + 3 = 6! ); for every factor of 4 increase in distance, the gravity decreases by a factor of 4 × 4 = 16 (not by 4 + 4 = 8! ), etc. See the mathematics review appendix for a review of ``factor'' and ``times''.
The maximum frictional force that must be overcome before movement is able to begin is μsFN. If you apply a constant force to pull an object along a horizontal surface at a constant speed, then the frictional force opposing the motion is equal and opposite to the applied force, Fp. Therefore, Fp = Ff. The normal force is equal and opposite to the object’s weight when the object is on a horizontal surface and the applied force is horizontal. The question to be answered by performing this lab is how can the coefficient of static and kinetic friction be determined for an object on a horizontal surface?
So long as temperature remains constant the same amount of energy given to the system persists throughout its operation and therefore, theoretically, the value of k will remain constant. However, due to the derivation of pressure as perpendicular applied force and the probabilistic likelihood of collisions with other particles through collision theory, the application of force to a surface may not be infinitely constant for such values of k, but will have a limit when differentiating such values over a. Forcing the volume V of the fixed quantity of gas to
6) The procedure was then repeated for larger values of h, until T has passed its minimum value. (A smaller moveable knife edge must be used for values of h, as the axis of suspension lies on the narrow strip region of the pendulum) 7) A graph of T against h was then plotted and the value of h at which the period reaches a minimum should be estimated. 8) A graph of hT2 against h2 was then plotted and analysed to obtain a value for g. As a means of obtaining the value for g, the results were used to produce a straight line graph and the gradient of the graph used to find the value of g. The period of the pendulum is given by; T=2πω=2π(k2+h2)gh Squaring both sides of this equation gives; T2=4π2ghk2+h2 This re-arranges to give; hT2=4π2g×h2+4π2g×k2 Which is the form y=mx with y=hT2,