# Explain Why Equal Masses Of Golf Balls Contain The Number Of Water Molecules

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Chapter 2 Exercises 2. How many individual atoms are in a water molecule? • 6 : 4 hydrogen 2 oxygen 4. The average speed of a perfume-vapor molecule at room temperature may be 300 m/s but you’ll find the speed at which the scent travels access across the room is much less. Why? • There isn't a free path for the perfume vapor molecules to travel across the room. The molecules take a haphazard random path, constantly colliding with nearby air molecules. 6. If no molecules in a body could escape, would the body have any odor? • No, it is the minute molecules in the air that we detect in our nasal cavity and if there were no molecules given off then there would be no way to smell them. 8. Which of the following…show more content…
Your friend says that what makes one element distinct from another is the number of electrons about the atomic nucleus. Do you agree wholeheartedly, partially, or not at all? Explained • NO • What makes one element distinct from another is the number of protons in the nucleus. Hydrogen has 1, gold has 79, uranium has 92, etc. Not electrons. Protons. 12. Why don’t equal masses of golf balls and Ping-Pong balls contain the same number of balls? • Because the density of golf balls are so much higher than the density of ping-pong balls. 14. Which contains more atoms: 1 kg of lead or 1 kg of aluminum? • The atomic weight of aluminum is about 27. The atomic weight of lead is about 207. A single lead atom is almost 8 times heavier than a single aluminum atom. So you would need about 8 times the number of aluminum atoms compared to lead atoms to come up with the same weight. 16. The atomic masses of two isotopes of cobalt are 59 and 60. a) What is the number of protons and neutrons in each? • The protons are the same otherwise it wouldn't be cobalt = 27 So the remainders are neutrons = 32 or 33 b) What is the number of orbiting electrons in each when the isotopes are electrically neutral? • Electrons = protons = 27, if electrically