Conservation Of Energy Experiment

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Title: Thermal Energy Report Name: Bardia Sepehrnia Date: 05-10-2011 Experiment Nr. 1 Purpose: check and prove the conservation of energy law. Data collection: In this experiment, we got 2 glasses of waters with different temperatures. Thermometer is used to measure the water temperature. The mass of the water should also be measured using scale. In order to do that first we measure the mass of the empty glass and then we measure the mass of the glass filled with water. By subtracting the mass of glass with water from the mass of empty glass we will get the mass of water Results: m cold = 87.7 g T cold = 20.5 OC m hot = 78.6 g T hot = 44.6 OC Data processing: we add 2 glasses of water together and we measure the common temperature using thermometer. After that we can find the temperature change (ΔT) by subtracting the common temperature from the initial temperature. (ΔT = T1 – T0) Common Temperature: 30.8 |30.8 – 20.5| = 10.3 ΔT cold = 10.3 OC |30.8 – 44.6| = 13.8 ΔT warm = 13.8 OC Now we will use the formula E = m.C.ΔT to measure the amount of energy transferred for both cold and hot water. E: Transferred Energy J m: Mass kg C: Specific Heat Capacity J/g.OC ΔT: Temperature Change OC E cold = 0.0877 × 4.2 × 10.3 ≈ 3.794 kj E warm = 0.0786 × 4.2 × 13.8 ≈ 4.555 kj Conclusion: According to conservation of energy law, E cold should be equal to E warm as we know the total amount of energy in an isolated system remains constant over time. That means energy can neither be created nor be destroyed: it can be transformed from one form to another or transferred from one place to another. But in this example we do not have an isolated system because the factor air is existed in the system and it will effect on the experiment result as air itself will take a part in energy transfer. Also Thermometer takes a long time to measure the temperature which will

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