A plant whose cells are in a hypertonic solution will appear droopy because there is a loss of turgor pressure in each cell. When the concentration of water is the same in the cell and the solute the cell is said to be isotonic and is at equilibrium. There is no net movement of water across the membrane. (Biology Department, 2010). Surface area to volume ratio has a direct effect on the amount of water (as well as nutrients and waste) that can diffuse through the plasma membrane.
It is important for an IV solution to have salts in it so the water and solute can be equal to create an isotonic environment. If there wasn’t, there would either be a hypotonic causing the cell to burst, or there would be hypertonic causing the cell to shrink. We created models of living cells by using dialysis tubing. The dialysis tube represented the cell membrane to act as selectively permeable to water and some solutes. We observed different solutes (NaCl, Ovalbumin, Glucose, Sucrose, and Water) in the dialysis tubing.
Osmolarity involves the movement of water across a cell membrane which is osmosis, this movement of water can be hypertonic; a higher concentration of a solute inside the cell which means the cell loses mass, hypotonic; a lower solute concentration inside the cell than outside which means the cell gains mass, or isotonic; a solute concentration the same as the outside of the cell which means there is no net movement of water. In a hypertonic solution in a cell water will leave the cell in order to balance the solute concentration making the cell shrink, in a hypotonic solution however water will enter the cell to balance the concentration. In an isotonic solution water will not move since both sides are equal in concentration. b. Purpose-The purpose of this lab was to determine the osmolarity of plant cells by using potato cores as the cells and sugar as the solute. c. Hypothesis-My hypothesis was that if the amount of solute increases then the then potato core’s weight decreases.
Blood is a bodily fluid that delivers substances such as oxygen and nutrients to the cells and removes waste products from them. All vertebrates have blood and in humans, blood travels in a double circulated system in which oxygenated blood and deoxygenated blood work separatly. Some vertebrates, such as the counter-current mechanism in fish, have single circulatory system. There are four constituent parts in blood which are the blood plasma, red blood cell, platelets and white blood cells. Plasma and red blood cells transport substances to or away from cell.
Smaller solutes and fluid pass through the membrane, but the membrane blocks the passage of larger substances (for example, red blood cells, large proteins). This replicates the filtering process that takes place in the kidneys, when the blood enters the kidneys and the larger substances are separated from the smaller ones in the glomerulus. a process by which molecules of a solvent tend to pass through a semipermeable membrane from a less concentrated solution into a more concentrated one, thus equalizing the concentrations on each side of the membrane. In this lab, one will observe the properties of diffusion and osmosis and model the data one receives on a standard curve. With knowledge of water potentials, one can chart the gains and losses of water to find the molarity of a specific solution.
This is a diffusion where the movement of water from an area of high water concentration is moved to an area of low concentration. This experiment takes place to measure the diffusion of small molecules throughout dialysis tubing. This tubing acts as a selectively permeable membrane, allowing the larger molecules to pass through, but slowly. When the two solutions on either sides of the membrane are equal and no net movement is detected, the solutions are isotonic. This means that the solutions have the same concentration of solutes.
When these factors vary, enzymes may change in shape so it will not be able to bond to the specific substance anymore. What is trypsin? Trypsin is produced in the pancreas as typsinogen originally allowing metabolic control. It is used widely in various biotechnological processes because it is very easy to be purified. Method: Material: • Trypsin • Casein • Water bath (to keep the temperature constant) • Colorimeter (to measure the rate of enzyme activity) • Thermometer • Test Tubes (to contain the casein and the buffer solution) • Stop watch (to control and measure the time) • Distilled water (to mix with trypsin to produce the buffer solution) • Test tube rack (to prevent the tubes rolling and smashing) Protocol: • Put 2.5 cm³ of 5% with reconstituted casein in 6 of the test
Digestive enzymes are hydrolytic enzymes. Their substances, or the molecules on which they act are organic food molecules which they breakdown by adding water to the molecular bonds, thus cleaving the bonds between the subunits or monomers. Digestive enzymes can function outside the body cells; their activity can be studied by test tubes (Marieb and Mitchell 2010). This experiment attempts to re-create the breakdown process that is normally done via digestion with Iodine as a vital component. It can be expected that once amylase reacts with the starch, maltose will then be broken down and less starch will be visible and more sugar will be apparent thus causing the solution mixed with iodine to become lighter and lighter.
With osmosis and diffusion requiring no energy it is key for the cells to make sure that they can make maximum advantage of both to conserve energy and maintain homeostasis. With the use of diffusion and homeostasis it is important to truly see the effects that occurs when they are recreated with controlled variables. Part 1 Agar cubes are prepped with 1% phenolphthalein which would indicate the pH with relation to their color. These cubes are all different sizes with all of the cubes being submerged in a acetic acid solution. With the submersion of the cubes in acid the differentiation will be key in proving that each of the cubes has a different absorption rate.
As the Sephadex forms a network with tiny holes, this prevents molecules that are too large from getting inside. The buffer also helps the protein molecules that are too large to enter the gel to bypass the gel altogether by flushing them out. It is for this reason that the protein with the largest molecules will be eliminated first and the protein with the smallest molecules should be eliminated last as they are able to pass right through the gel. Therefore the smallest molecules are able to deeply penetrate the gel and remain in the column for longer while, as the size of the molecules increases, the molecules are less able to do so and are eliminated quicker. Experimentation Throughout the experiment great care was taken when handling all substances.