In what units will we measure enzyme activity? (2 points) 11. Which 2 enzymes are we following & where is each found? (4 points) 12. a. With which instrument will we measure the amount of product formed by the enzymatic reactions?
The dependant variable of this experiment will be the rate of reaction of the enzyme catecholase with its substrate catechol. The independent variable of this experiment is the various pH levels that the catecholase and catechol are exposed
Name: Marc Dickson Course: Biology 100 Date: 2/7/2014 Lab Title: (Enzyme Controlled Reactions) Question: How do substrate concentration and pH affect enzyme controlled reactions? Introduction: Part of the enzyme is called the active site...The substrate binds to this part of the enzyme. The active site is shaped in a certain way that is coded to fit with its substrate. If the substrate has the right shape to attach itself to the enzyme's active site, it will. I will investigate and determine the effects of substrate concentration and pH on the initial rate of an enzyme-catalyzed reaction.
1) ABSTRACT The purpose of this experiment was to carry out the effects of enzyme concentration, temperature, pH level, and an inhibitor on a type of enzyme called Perixodase. The purpose of the experiment was also to understand the relationship between the change in absorbance with time and the enzyme reaction rate. To perform the experiment, the class was divided into groups. Each group took on one of the factors affecting the enzyme. Before beginning the actual experiment, we used the mixing tables that were given to us to set up the test tubes with the appropriate substances.
Objectives: The purpose of this lab is to observe the reaction of crystal violet and sodium hydroxide by looking at the relationship between concentration and time elapsed of the crystal violet. CV+ + OH- CVOH To quantitatively observe this reaction of crystal violet, the rate law is used. The rate law tells us that the rate is equal to a rate constant (k) multiplied by the concentration of crystal violet to the power of its reaction order ([CV+]p) and the concentration of hydroxide to the power of its reaction order ([OH-]q). Rate = k[CV+]p[OH-]q To fully understand the rate law, concentrations of the substances must be looked at first. The concentration is measured in molarity.
Use a calorimeter to measure the temperature change in each of three reactions. Calculate the heat of reaction, ∆H, for the three reactions. Use the results to confirm Hess’s law. Ev al Figure 1 ua tio Na+(aq) + OH–(aq) + H+(aq) ) + Cl–(aq) → H2O(l) + Na+(aq) + Cl–(aq) ∆H3 = ? n (3) Solutions of aqueous sodium hydroxide and hydrochloric acid react to form water and aqueous sodium chloride.
Controlled Variables. temperature; pH; sucrase + sucrose incubation time 4. Describe what is measured as an indicator of sucrase activity and why this is an indicator of sucrase activity. The amount of product produced is an indicator of sucrase activity. This is an indicatore because sucrase is an enzyme found in the small intestine that catalyzes the splitting of the disaccharide sucrose into the monosaccharides glucos and fructose.
Record your hypothesis on page 123. -My hypothesis is we can determine the different between each chemical reaction by the temperature change.To descide which one is exothermic and endothermic. 4. Summarize the procedures you will follow to test your hypothesis. -We measured in each chemical and added water besides, HCl we added NaOH.
The specific heat constant for water, 4.184 J/g C, is used for this equation. The specific heat can be found by using The Law of Dulong and Petit: Eq. 3 Cs(aluminum) = slope x 1/atomic weight This equation is used to find specific heat from the graph that will be drawn based on the results of the metal specific heats. II. Materials and Procedure See General Chemistry 101/102 Laboratory Manual (pg.
Internal Assessment I Aim: Investigate a factor affecting the rate of enzyme activity. Research Question: What is the effect of the different concentrations (0.6%, 1.2%, 1.8%, 2.4%, 3.0%) of the substrate hydrogen peroxide (H2O2) towards the rate of reaction with the enzyme catalase found in yeast? Variables: | Units, Range, Uncertainty: | Measured using: | Independent Variables | Different concentration of hydrogen peroxide (0.6%, 1.2%, 1.8%, 2.4%, 3.0%) | A volumetric flask and measuring cylinder (to dilute the 3.0% hydrogen peroxide) | Dependent Variables | Rate of reaction (cm3s-1) | A measuring cylinder and stop watch (to measure the amount of foam produced against a specified time, thus finding the rate of reaction) | Hypothesis: Prediction, based on observations: | Annotated sketch graph to show predicted outcomes: | If the rate of activity of an enzyme catalase is related to the concentration of the substrate, then with an increased concentration of H2O2, I predict that there will also be an increase in the volume of foam produced by the reaction between the catalase enzyme found in the yeast and the hydrogen peroxide, signifying the increase in the rate of enzyme activity. The least amount of foam will be produced when yeast is reacted with hydrogen peroxide solution of the lower concentration (in this experiment’s case, lowest being 0.6%), signifying the lower rate of reaction when the substrate concentration is lower. On the other hand, the most amount of foam will be produced when yeast is reacted with the hydrogen peroxide with a higher concentration (in this experiment’s case, highest being 3.0%), signifying a faster rate of reaction when the substrate concentration is higher.