So, if we take random values for r2 between 0 and 1 then we will get different values of time intervals in weeks between successive breakdowns. 3. Lost revenue It is given that they charge $0.10 per copy and number of copies sold in one day follows a uniform probability distribution between 2000 and 8000 copies. Therefore, if we chose a random variable r3 whose value is in between 2000 and 8000 then the lost revenue will be 0.1×r3×repair time. By putting different values for r3, we can get a number of lost revenues by simulation method.
Which would have the longer wavelength, light with a frequency of 4.5 X 1014 Hz or light with a frequency of 6.19 X 1014 Hz? (4.5 X 1014 Hz) ______________12. Find the frequency of light if its wavelength is 7.3 X 105 5 picometers. (4.1 X 1014 Hz) ______________13. Find the wavelength in centimeters of light whose frequency is 7.00 X 1016 Hz.
,Sarah L. G January 6, 2013 Written Assignment #1 1. A) $1,000 with 5% interest after 10 years gives you $1,628. Therefore, you would gain $628 in interest. B) If the interest is withdrawn each year, a total of $500 would be earned because the $1,000 investment would earn $50 of simple interest each year. C) The answers are different because if the interest is left untouched, it makes the principal amount higher each year, giving more money after 10 years.
1.328 b. 2.539 c. 1.325 d. 2.528 ANSWER: a -go to the t-dtistrubution and use α=0.20 or confidence of 80% and use dof=19 3. Read the t statistic from the table of t distributions and circle the correct answer. A one-tailed test (upper tail), a sample size of 18 at a .05 level of significance t = a. 2.12 b.
p.286. no 10.- Two hundred draws will be made at random with replacement from the box -3, -2, -1, 0, 1, 2, 3 (a) If the sum of the 200 numbers drawn is 30, what is their average? (b) If the sum of the 200 numbers drawn is –20, what is their average? (c) In general, how can you figure the average of the 200 draws, if you are told their sum? (d) There are two alternatives: (i) Winning $1 if the sum of the 200 numbers drawn is between –5 and +5 6 Winning $1 if the average of the 200 numbers drawn is between –0.025 and +0.025.
Use the report pages below to record your data. Answer questions A-G found on pages 46 and 47. Name: _________________________ Lab 2 Report Data: Data Table 1: Length Measurements | Object | Length (cm) | Length (mm) | Length (m) | CD or DVD | 12.1 cm | 121 mm | .121 m | Key | 5.1 cm | 51 mm | .051 m | Spoon | 16.1 cm | 161 mm | .161 m | Fork | 18.5 cm | 185 mm | .185 m | NOTE: The instructions indicate to measure the objects to “one degree of uncertainty.” The degree of uncertainty is a property of the instrument used. All three recorded values will have the same precision. On page 29 is the explanation of uncertainty.
Examine the Sample data in Table 1. a. Which fiscal quarter is most likely to contain the extra week? Q: Panel B of Table 1 shows that most firms include the additional week in their fourth fiscal quarter (77.06%). b. What are the most popular days chosen for the last day of the fiscal year?
TOPIC 8 Chi-Square goodness-of-fit test Problem 12.1 Use a chi-square goodness-of-fit to determine whether the observed frequencies are distributed the same as the expected frequencies (α = .05) Category | fo | fe | 1 | 53 | 68 | 2 | 37 | 42 | 3 | 32 | 33 | 4 | 28 | 22 | 5 | 18 | 10 | 6 | 15 | 8 | Step 1 Ho: The observed frequencies are distributed the same as the expected frequencies Ha: The observed frequencies are not distributed the same as the expected frequencies Step 2 df = k – m – 1 Step 3 α = 0.05 x 2 0.05, 5df = 11.0705 Step 4 Reject Ho if x 2 > 11.0705 Category | fo | fe | | 1 | 53 | 68 | | 2 | 37 | 42 | | 3 | 32 | 33 | | 4 | 28 | 22 | | 5 | 18 | 10 | | 6 | 15 | 8
1. The graph approximates the points: E(r) σ Minimum Variance Portfolio 10.89% 19.94% Tangency Portfolio 12.88% 23.34% 10. The reward-to-variability ratio of the optimal CAL (using the tangency portfolio) is: 11. a. The equation for the CAL using the tangency portfolio is: Setting E(rC) equal to 12% yields a standard deviation of: 20.56% b. The mean of the complete portfolio as a function of the proportion invested in the risky portfolio (y) is: E(rC) = (l - y)rf + yE(rP) = rf + y[E(rP) - rf] = 5.5 + y(12.88 - 5.5) Setting E(rC) = 12% ==> y = 0.8808 (88.08% in the risky portfolio) 1 - y = 0.1192 (11.92% in T-bills) From the composition of the optimal risky portfolio: Proportion of stocks in complete portfolio = 0.8808 × 0.6466 = 0.5695 Proportion of bonds in complete portfolio = 0.8808 × 0.3534 = 0.3113 12.
Exams (55%): There will be three 90-minute exams, tentatively scheduled for 7/15, 7/25, and 8/1. The two best exam scores will each be worth 20% of your final grade, and the worst of the three will be worth 15% of your final grade. Only under acceptable circumstances (ie. university policy) will make-up exams be given. 3.