K12_1821161 $100 Answer from 1 Jan 9, 2014 1:03:23 PM Page 6. Blackboard Collaborate ?? K12_1821161 $200 Question from 1 Jan 9, 2014 1:03:23 PM
100. g Al reacts with excess O2 to produce 150. g Al2O3 according to Calculate the theoretical and percentage yield. 4Al + 302 → 2 Al2O3. 79.4 % 14. Calculate the energy produced by the complete reaction of 150. g H2. 2H2 + O2 → 2H2O + 130KJ 4.83 x 103 kJ 15.
Here is how we think about it: It is $100 for the first 10 feet. After that it is $25 for each additional 10 feet. This tells us that it is arithmetic sequence because we are multiplying. N= the number of terms altogether N= 8 D= the common difference D=25 A1= the first term A1= 100 An= the second term An= a8 Next, we need to compute what a8 is. An= a8+ (n-1) d A8= 100+ (8-1)25 A8=100+7(25) A8=100+200 A8=300 Now that we know what A8 is, we need to know what the sum of the sequence is from A1 to A8.
(My calculator doesn’t go that far, ha.) Cost of Hard Drive Space per GB: In 1980, the price per GB was roughly $100,000. Today, it would not even cost a dollar. Based on the chart above, the space per unit cost has roughly double every 14 months. ”Several terabyte+ drives have recently broken the $0.10/gigabyte barrier, making the next milestone $0.01/gigabyte, or $10/terabyte.” (Komorowski, 2009) With Moore’s law in effect, I believe we will see a 100 TB hard drive within the next twenty years.
ACCT 550 Week 7 Homework Chapter 11: E11-4, E11-9, E11-11, E11-17 E11-4 (Depreciation Computations—Five Methods) Wenner Furnace Corp. purchased machinery for $279,000 on May 1, 2012. It is estimated that it will have a useful life of 10 years, salvage value of $15,000, production of 240,000 units, and working hours of 25,000. During 2013, Wenner Corp. uses the machinery for 2,650 hours, and the machinery produces 25,500 units. Instructions From the information given, compute the depreciation charge for 2013 under each of the following methods. (Round to the nearest dollar.)
You can purchase the devices together as a single combination unit called an optical loss test set (OLTS) or as separate units in a fiber-optic test kit. The Time-Domain Reflectometers is the primary tool used to determine the length of a copper cable and to locate the impedance variations that are caused by opens, shorts, damaged cables, and interference with other systems. Two basic types of TDRs are available: those that display their results as a waveform on an LCD or CRT screen and those that use a numeric readout to indicate the distance to a source of impedance. You can use a TDR to test any kind of cable that uses metallic conductors, including the coaxial and twisted-pair cables used to construct LANs. A high-quality TDR can detect a large variety of cable faults, including open conductors; shorted conductors; loose connectors; sheath faults; water damage; crimped, cut, or smashed cables; and many other conditions.
75uS is the time constant used for a high-pass filter to enhance the high frequency audio before transmission to help reduce noise upon reception. The PLL is the portion of the IC which locks your chosen transmission frequency to the crystal reference X1. The PLL portion also contains an oscillator circuit which works in conjunction with the external parts of D5 and the STUB (that weird trace on the back of the board). D5 is called a varactor diode, and is a special variety of diode that is connected backwards. As a reverse DC voltage is applied across the diode, its capacitance varies.
The electricity cost was charged on a quarterly basis and charged back to each department on a quarterly basis also. The quarterly costs were September 2013 $13000, December $11000, March $10000 and June $11000. Retail Banking make payment of 100% of the cost up front as they are the controlling department. Retail Banking then process an adjusting entry to Commercial Banking’s cost centre for 30% of the expense and an adjusting entry to Financial Planning’s cost centre for 10% of the expense which together with its 60% obligation brings the total to 100%
The following data were provided for production results for the current month. 0 Units, beginning work-in-process 300 Units started ? Units completed 100 Units, ending work-in-process (40% complete) Which are the equivalent
Figure 2 shows a circuit with a resistor R = 1.0 × 103 Ω, and a battery with potential difference of VB = 5.0V . (a) Solve the circuit in Figure 2. That is, find all unknown currents, voltages, and resistances. (b) What is the direction of the current? Note: I want the direction of the conventional current.