The second part of the procedure holds F constant and investigates the relationship of a to m by altering the total mass of the system. Again, based on the equation a = F/m, acceleration and mass should be inversely related to each other. m = k/a and a = k/m. 2. PROCEDURE 2.1 Equipment & Materials The key piece of equipment used in this investigation is the Atwood machine.
JOULES=1 newton of force moving an object 1 meter. 2. Explain what potential energy is and write out the equation we use to solve for it! PE = weight x height or PE = mass x 9.8 m/sec2 x height 3. Explain what kinetic energy is and write out the equation we use to solve for it!
As the athlete is spinning the hammer in a circle there is force acting upon it and that mean Newton’s Laws are relevant to the situation. The circular movement of any object depends on the three Newton’s Laws. 1. If a body is at rest, it will remain at rest unless the forces acting upon it become unbalanced. 2.Force is equal to mass times acceleration.
Only the rate at which other objects spin around it. A more massive planet requires that a moon be traveling faster to keep it in orbit. Anything slower would "fall" into the planet. The heavier the planet, the faster the object needs to be to stay in orbit. Here is an example: On Earth, an object needs to be travelling at roughly 18,600 miles per hour to stay in orbit.
The closer the planet is, the faster the speed. Third law establishes a relation between the average distance of the planet from the sun and the time to complete one revolution around the sun. The ratio of the semimajor axis is the same for all planets including earth. Issac concluded the attractive force exsiting between any two particles of matter is defined as gravitation. Sir Issac fully recognize the force holding any object to the earth is the same force that holds the moon, planets, and other heavenly bodies in their orbits.
It is a function of the objects mass and velocity. Mass (weight) x Velocity (speed) 2 Kinetic energy =
Background Theory & Physics Ideas When Newton outlined his second law of motion, he did not describe it in the way we use it today. He talked about a property of a moving object that he called its 'motion'. He said that when a force acts on an object for some time interval, its 'motion' would change. Today, we call this quantity the momentum of the object. In fact, Newton's first law could be stated as 'in the absence of unbalanced forces, the momentum of an object will be constant'.
Student designed practical investigation Title: Atwood’s Machine (Newtons 2nd law of motion). Partner: Qurban Aim: To explore how two different masses act with each other on a pulley and therefore calculate acceleration a (theoretical and experimental) and the Tension T. Hypothesis: When both masses are the same, there should be no acceleration. The larger the ratio between one mass and the other, the higher the acceleration should be. Materials: Pulley, string, mass 1 + 2, ruler, stopwatch, scissors Apparatus: Theory: Since we are trying to find a, the equations we need are: For experimental a: Transposed to: Theoretical a: For tension: where x = displacement u = initial velocity t = time taken = mass 1 = mass 2 Let Method: 1. Set up the apparatus in the diagram above.
Centripetal Force is the radial force which acts ON a rotating mass and Centrifugal Force is the radial force which is exerted BY a rotating mass. (1b) Centripetal Acceleration is the inwards acceleration necessary to maintain circular motion. If a point moves at uniform speed in a circular path, its direction is continually changing and, therefore, though its speed is constant its velocity is changing. Acceleration is defined as “rate of change of velocity with respect to time” Centripetal Acceleration (a) = v² (Linear Velocity) r Centripetal Acceleration (a) = w²r (Angular Velocity) (2)a Mass 1000kg (m) Radius of Curve 45m (r) Coefficient Friction 0.7 (u) Track of Vehicle 1.5m (d) Centre of Gravity 0.68m (h) Acceleration (force of gravity) 9.81 m/s² (g) Without skidding outwards, Centrifugal force = Frictional resistance to skidding = m v² = u m g r Max Speed v = √u g r =√ 0.7 x 9.81 x 45 =√ 309.015 = 17.5788 m/s Convert to km/h = (17.5788m/s x 3.6) = 63.3 km/h Without overturning, Overturning moment = Righting moment = m v²h = m g d r 2 Max Speed V = √g r d 2 h =√ 9.81 x 45 x 1.5 2 x 0.68 =√ 225.1395 = 15.0046 m/s Convert to km/h = (15.0046m/s x 3.6) = 54 km/h (2)b Rotating Bobs 250g (each) Spring Strength 8 kN/m Centre Mass of Bob 160mm radius (resting) Balance of forces = F + R = Mw²r At Engagement, F = Stiffness x Extension = 8 x 1000 x
Physics 215 September 13, 2011 Experiment Number 3 Acceleration Due to Gravity Introduction The purpose of this experiment is to measure the acceleration due to gravity of a free falling object. By performing Galileo’s experiment of free falling objects to measure the acceleration due to gravity. This experiment is based on the Galilean theory of free fall, and there are two important characteristics regarding free fall: (1) Free fall objects do not have air resistance and (2) All free falling objects on Earth experience a downward acceleration of 9.8 m/s2. This experiment will prove that the weight of an object does not determine how fast it will fall, despite Aristotle’s claim. Theory In this experiment we will be interested in only one direction of motion.