Hareem Qureshi Group 6 Presentation Lab 6: Grand Central Equation Focus Questions: * Zinc Iodide can be gained through more than one method. We experienced making Zinc Iodide through zinc granules and iodine chips first and then we used Barium Iodide and Zinc Sulfate to make the zinc iodide. Chemists should prepare Zinc Iodide from its Elements rather than using double replacement reaction between Barium Iodide and Zinc Sulfate. In comparison to the grand central equation lab, the castle of quantification lab proves several benefits of using just Zinc and Iodine in formation of Zinc Iodide. Zn + I2 ⟶ ZnI2 | BaI2·2H2O +ZnSO4·7H2O⟶ZnI2+BaSO4+9H2O | Zinc used: (2g x $0.0625)=$0.125Iodine used:(3g x $0.1003)=$0.301Material cost for 3.1g of ZnI2 =$0.498Material cost for 10g of ZnI2 = $1.6 | 0.48g of Zinc Sulfate heptahydrate used= $0.01940.62g of Barium Iodide dehydrate used= $0.549Material cost for 0.48g of Zinc Iodide= $0.5684Material cost for 10g of ZnI2 = $11.84 | % Yield from Zn and I2 reaction: 98.6%% Error: 1.39% | % Yield from BaI2·2H2O and ZnSO4·7H2O reaction:103.6%% Error: 3.6% | The data above shows that Zinc Iodide formation through elements is much more efficient than using compounds.
2Al + Fe2O3 ( Al2O3 + 2Fe (26.98) ( 159.7) (101.96) 124 601 80 b. Al c. 234.3 d. 234 e. 34.1% 1c. A strip of zinc metal with a mass of 2.0g undergoes single displacement reaction with an aqueous solution containing 2.5g of silver(I) nitrate A. Write a balance equation for the above reaction B. Which of the 2 reactants is the limiting reagent? C. Calculate the mass of zinc (II) nitrate formed D. How much excess reagent is left at the end of the reaction?
The zinc most likely functions as a(n) | | | | | Selected Answer: | cofactor necessary for enzyme activity. | | | | | * Question 7 1 out of 1 points | | | Which of the following is a statement of the first law of thermodynamics? | | | | | Selected Answer: | Energy cannot be created or destroyed. | | | | | * Question 8 1 out of 1 points | | | Which of the following statements is (are) true about enzyme-catalyzed reactions? | | | | | Selected Answer: | The reaction is faster than the same reaction in the absence of the
Reduction and Recovery of Copper Name Here March 18, 2015 Purpose: The goal of this experiment was to use redox chemistry to obtain a sample of copper from a copper (II) sulfate solution. This was accomplished by adding zinc to the copper (II) sulfate solution so that the zinc bonds to the sulfate and leaves copper. Method: To obtain copper from a copper (II) sulfate solution, the copper needs to go through reduction; this means another element has to go through oxidation. For this experiment, zinc was the element going through oxidation. First, we had to calculate how many grams of copper (II) sulfate we needed to form 100 mL of a 0.200 M solution of copper (II) sulfate.
1 mol of Zn Multiplied by the mole ratio of Zn to Cu(A) 2 mol of Cu(A) in the reaction. 65.39 grams of Zn Multiplied by the molar mass of Zn 1 mol of Zn = 0.1918 grams Zinc Any amount of Zinc that is 0.1918 grams or less makes Zinc the limiting reactant in the reaction of Cuprous (Cu+1). I will use 0.70* grams of Zinc. The ratio of moles
If a similar plot to the one you made in class was made using lead instead of zinc, what numerical value would the slope of the line be close to? Make a fast linear plot for lead and then superimpose the plot for zinc onto it. What does this tell you about their densities? The slope of the line would be close to 11.3. This is so because the slopes of these graphs signify the density of the substance, which is in this case, is lead.
Task 3 (D4) Choose one primary and one secondary cell and evaluate their use for portable applications. Primary – (silver oxide cells) Zinc-silver oxide cells effectively use the high electrode potential of silver to produce a high energy density that is combined with a flat discharge curve. This is done as silver oxide forms a positive anode for the cell which could also be mixed with little amounts of manganese dioxide. The metallic zinc in the battery powers the negative electrode which is formed into a gel like substance with the electrolyte usually sodium hydroxide or potassium hydroxide. A separator membrane will then be infiltrated between the negative electrode gel and positive electrode preventing them from being mixed together which would make the battery useless if not in place.
Who is right, John or Anna? Explain your answer. 3 When 200 g of calcium nitrate, Ca(NO3)2.2H2O is heated at 120ºC the mass decreases by 36 g. (a) Why does the mass decrease? (b) How much calcium nitrate is left after heating? 4 Calculate the molar mass of these compounds: (relative atomic masses: H = 1; N = 14; O = 16; S = 32; Cu = 64; Br = 80; Pb = 207) (a) copper nitrate, Ca(NO3)2 (b) lead bromate, Pb(BrO3)2 (c) ammonium sulfate, (NH4)2SO4 5 The equation for the complete combustion of methane is shown below.
The zinc granules will provide unaccurate results. 1b. Will the density of zinc using granules be greater or smaller? We know that density = mass/volume. Therefore, if zinc granules provide a larger volume with a constant mass, the density would be much smaller.
Ideal gas law exam lab 1. purpose: to find the amount of H2 gas that is produced between a reaction of HCl acid And magnesium 2. Background: the balanced equation for magnesium reacting with an excess amount of Hydrochloric acid (HCl) is: Mg + 2HCl MgCl2 + H2 in this lab/experiment HCl acid will be an excess so for each mole of magnesium there should be a yield of one mole of H2 gas and the magnesium will be the limited reactant. Due to the conservation of mass laws (matter cannot be lost or destroyed) as the HCl acid dissolves the magnesium there is a gas produced, theoretically it should weigh as much as the magnesium that was dissolved. Hydrogen gas (H2) is colorless, odorless and the most abundant element in the universe. Hydrogen combines with oxygen to make water which is essential to life Hydrogen gas (H2) is colorless, odorless and the most abundant element in the universe, it is less dense than air or water.