# Determination Of Copper Metal Ions Through Reactio

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Determination of Copper Metal Ions Through Reactions with Zinc Aim: The aim of this experiment is to determine which of the common copper ions, Cu+1 and Cu+2, is present in each of two unknown copper compounds, and whether or not the copper compounds contain the same copper ion. Nomenclature: Light blue substance: LB Dark blue substance: DB Preliminary Calculations: Identify the available test metal with the highest ionization energy. The available test metal with the highest ionization energy is Zinc. Because Zinc has the highest ionization energy (904) compared to Magnesium (736), and Aluminium (578), Zinc will be used in this experiment. Create reactions with anion placeholders for copper compound and Zinc. If the copper is cuprous, or Cu+1, the reaction is: 2Cu+1(A-1) (aq)+ Zn+2(s) Zn+2(A-1)2 (aq)+ 2Cu+1(s) (A= anion) If the copper is cupric, or Cu+2, the reaction is: Cu+2(A-1)2 (aq) + Zn+2(s) Zn+2(A-1)2 (aq) + Cu+2(s) Calculate the grams of Zinc needed for the reaction if copper compound is cuprous (+1) or cupric (+2). If the Copper is Cuprous: 2Cu+1(A-1) (aq) + Zn+2 (s) Zn+2(A-1)2 (aq) + 2Cu+1(s) Grams of Zn = 1 gram of Cu(A) The amount of Cu(A) that will be used. 1 mol of Cu(A) Divided by the molar mass of Cu(A) 170.49 grams of Cu(A) as given by the instructor. 1 mol of Zn Multiplied by the mole ratio of Zn to Cu(A) 2 mol of Cu(A) in the reaction. 65.39 grams of Zn Multiplied by the molar mass of Zn 1 mol of Zn = 0.1918 grams Zinc Any amount of Zinc that is 0.1918 grams or less makes Zinc the limiting reactant in the reaction of Cuprous (Cu+1). I will use 0.70* grams of Zinc. The ratio of moles