Chapter 1 review questions 1. Which of the following is true about 1 bit? a. Can represent decimal values 0 through 9 b. Can be used to represent one character in the lowercase English alphabet c. Represents one binary digit d. Represents four binary digits 2.
Exercise 1.3.1 What is the decimal value of Byte 1 by itself? What is the decimal value of Byte 2 by itself? -6400 -233 Exercise 1.3.2 What is the decimal equivalent of the binary sequence in Figure 1- 12 (the combined sequence of Byte 1 and Byte 2 as a single decimal value)? How does this compare to the individual values of Byte 1 and Byte 2? -6633 -There is an increase of bits.
This can be displayed on a time line: | | | | | $P | $400,000 | | | | | | 0 | 90 | 180 | 270 | | | | | | | | | P | = | price | = | unknown | | S | = | Maturity value | = | $400,000 | | r | = | Simple interest rate (decimal) | = | 9.16 | 100 | | = | 0.0916 | | t | = | Time period (years) | = | 90 | 365 | | = | 0.24657534... years. | | The step-by-step calculation is: P | = | S(1 + rt)-1 | | = | 400,000(1 + 0.0916 x 0.24657534...)-1 | | = | 400,000 x 0.97791257...
5) Information about Clearwater Company's direct materials cost follows: Standard price per materials ounce $ 100 Actual quantity used 8,700 grams Standard quantity allowed for production 9,100 grams Price variance $ 76,125 F ________________________________________ Required: What was the actual purchase price per gram? (Round your answer to 2 decimal places. Omit the "$" sign in your response.) Actual purchase price $ 91.25 Total grade: 0.0×1/1 = 0% Feedback: Actual Costs = AP × 8,700 Actual Inputs at Standard Price = $100 × 8,700 =$870,000 Price Variance = $76,125 F 8,700 × AP = $870,000 – $76,125 AP = $91.25 ________________________________________ Question 3: Score
Both of these formulas were found on page 225 in Mathematics in Our World (Bluman, 2005). Problem #37 • This sequence is geometric • Ending balance is $814.45 STEPS/CALCULTATIONS YOU PERFORMED TO REACH THE ANSWER: To find the ending balance, the formula of An = a1(rn-1) will be used. The initial balance is $500, the interest is 5%, and the time span is 10 years. 5% will be listed as 1.05 as the initial balance is 100% plus 5% interest, so 105% is written 1.05. The number of terms is n=10, the first term is a1=525, the common ratio is r = 1.05.
Randy Michael NT 1210 Lab 1.1 Professor Chibuzo Onukwufor 4/1/15 Lab 1.1 1: Convert the decimal value 127 to binary. Explain the process of conversion that you used. Decimal Number | Binary Number | Remainder | 127 - | 64 | 63 | 63 - | 32 | 31 | 31 - | 16 | 15 | 15 - | 8 | 7 | 7 - | 4 | 3 | 3 - | 2 | 1 | 1 - | 1 | 0 | Binary | 27 | 26 | 25 | 24 | 23 | 22 | 21 | 20 | Decimal | 128 | 64 | 32 | 16 | 8 | 4 | 2 | 1 | Conversion | 0 | 1 | 1 | 1 | 1 | 1 | 1 | 0 | I took the decimal and divided it by two giving 1 for the remainders and 0 if it did not have a remainder. 2: Explain why the values 102 and 00102 are equivalent. They are equivalent because they represent the powers of 10 3: Based on the breakdown of the decimal and binary systems in this lab, describe the available digit values and the first four digits of a base 5 numbering system.
The first class in a relative frequency table is 50–59 and the corresponding relative frequency is 0.2. What does the 0.2 value indicate? Answer: ____Convert 0.2 to a % by times by 100. So 0.2 = 20%, so 20% of the data is between 50 and 59______________ 3. When you add the values 3, 5, 8, 12, and 20 and then divide by the number of values, the result is 9.6.
20. mol H2 reacts with 8.0 mol O2 to produce H2O. Determine the number of grams reactant in excess and number of grams H2O produced. Identify the limiting reactant. 8.1 g H2 , 2.9 x 102 g H2O 17. How many litres of O2 gas are required to produce 100. g Al2O3?
Electronic devices today use what numbering system? C. Binary 3. Convert this decimal number to binary: 97 A. 01100001 4. Convert this binary number to decimal: 00010000 D. 16 5.
10. In Excel, a number can contain the characters _____. (Points : 2) 0 1 2 3 4 5 6 7 8 9 + - ( ) , / . $ % E e all of