Abstract: The effect of temperature on solubility of potassium nitrate was demonstrated. This was done by dissolving the salt in distilled water at different concentrations and finding the temperature at which crystallisation occurred. From this a solubility curve could be formed. It was found that as the temperature increased, so did the solubility of potassium nitrate in distilled water. At 50C our results indicated a solubility of 89 g/100mL of H2O which was close to the known solubility of 80 g/100mL.
5. Record the data in a chart with the times. Experiment Basically the experiment is on what household items can insulate and hold the circulation of cold air inside the ice box which allows freezing points or melting points to take course. Data/ Graphs Ice Boxes | Test 1(none) | Test 2 (salt) | Test 3(Sugar) | Cardboard | 7:14.8 | 12:52.7 | 8:35.2 | Paper | 9:28.4 | 12:14.8 | 7:43.6 | Aluminum Foil | 16:35.1 | 17:21.6 | 13:17.8 | Time Graph Observations When I experimented I noticed that one of the ice boxes melted quickly than the others, which could mean that those ice boxes vents heat. The substance added to the ice box could have either helped it stay cool or melted it quicker.
The opposite of boiling is CONDENSATION (Boiling point is 100 degrees). This happens when molecules of gas start to stick together and form droplets of liquid. When water in a pan boils, for example, it turns to water vapour, which is an invisible gas. But almost immediately the water vapour condenses into tiny droplets in the air, which we call steam. Lastly, to get a liquid back to a solid, it simply needs to be FROZEN, (freezing point is 0 degrees) this can happen but putting the liquid in cold place for example a freezer where the temperature is below 0 degrees in order for it to change back to its original state.
Then we can use the formula to find the molar mass of the unknown organic compound. So that we will be able to presume what kind of organic compound the sample is. * Procedures outline: Sample type: Sample B * Methods: 1. We will use the ice-salt water bath to cool down the solution of sample B, because salt water can help it to be easier to get target temperature -7°C to -10°C. And it is also easier for the ice-salt water bath to main that temperature for longer time.
13. Placed the cup containing the water solution of benzoic acid and salt into the ice bath. Observed the benzoic acid crystallizing
The salt lowers the freezing point of the water/ice. This effect is called freezing point depression. Adding the salt to the ice will result in the melting of the ice by introducing dissolved foreign particles to it. The freezing point lowers as more particles are added until the salt stops dissolving. A latent heat of fusion will occur when the salt is introduced to he ice which will produce heat from the water changing phases also adding to the melting, and will keep the water in a liquid state.
FOUR UNKNOWN HOUSEHOLD OBJECTS Question: What are the four unknown household objects presented to us? Hypothesis: Substance 1 consists of water jelly crystals, if it turns into a jelly-like substance when mixed with water. Substance 2 is sugar, if it caramelizes when heated. Substance 3 is salt, if it lowers the melting point, and therefore melts ice faster than the other objects. Substance 4 is baking soda, if it fizzes when it reacts with baking soda.
Delta T= 18 M= 35 ml Starting Temp: 23 degrees Celsius Final Temp: 41 degrees Celsius q=(35)(4.184)(18) = 2,636 J q= -2,636 J released Conclusion: My hypothesis was correct. The water did in fact drastically rise as the sodium chloride was dissolving in the water. As a result, -2,636 Joules of heat was released from the chemical reaction with water and NaCl. The reaction was an Exothermic Process, because heat was released into the surroundings. The system in this reaction was the NaCl dissolving, and the surrounding being the
2Al + Fe2O3 ( Al2O3 + 2Fe (26.98) ( 159.7) (101.96) 124 601 80 b. Al c. 234.3 d. 234 e. 34.1% 1c. A strip of zinc metal with a mass of 2.0g undergoes single displacement reaction with an aqueous solution containing 2.5g of silver(I) nitrate A. Write a balance equation for the above reaction B. Which of the 2 reactants is the limiting reagent? C. Calculate the mass of zinc (II) nitrate formed D. How much excess reagent is left at the end of the reaction?
Put 15 drops of dilute (6 M) sodium hydroxide (NaOH), into each test tube and allow them to stand for at least 1 minute. This prepares the glass surface for the Tollens’ test. **Safety alert** Dilute NaOH should be used carefully. It attacks the skin and is especially damaging to the eyes. If any gets on the skin or in the eyes, wash it off immediately with cool water.