The second experiment, procedure 1, combined [Co(NH3)5 (H2O)]Cl2 (0.0060M, 1.52g) and (25mL) of distilled water to an 125mL Erlenmeyer flask. The flask was gently heated (dial 5-6) and stirred until all the compound was dissolved. The heated solution was then vacuum filtered through a fritted funnel and the filtrate was cooled in an ice bath until the
The chemical equation to be used is : 2NaHCO3(s) Na2CO3(s) + CO2(g) + H2O(g) In the second part, 1.0 M HCl will be titrated into a solution with a known amount of sodium carbonate (Na2CO3), the pH will be measured as it becomes more acidic and the equivalence point (the point at which HCL and Na2CO3 reach equilibrium) determined. We will calculate the moles of Na2CO3 by dividing the grams used by the molar mass of sodium carbonate. Then, the moles of HCl required to neutralize Na2CO3 will be determined by using the mole to mole ratio in the chemical equation. Finally, the molarity
This solution was added drop wise to the stirred ethanolic solution of benzophenone at room temperature. After all the sodium borohydride being added, the mixture was stirred for a further 10min. Meanwhile, ice water (10ml) was mixed with concentrated hydrochloric acid (1ml) in 50ml beaker. To this the mixture of sodium borohydride and benzophenone was poured slowly into the beaker. The precipitate was collected using suction filtration and washed with 2 x 5ml portions of water.
The bomb is filled to about 20 atm of pressure with O2, sealed, and placed in a known amount of water. An electric current is passed through a wire to ignite the mixture. As the combustion takes place, the heat evolved raises the temperature of the calorimeter and its surrounding water, as measured by a thermometer. In order to prevent heat loss from the calorimeter system, some calorimeters are surrounded by a second water bath, whose temperature is continuously adjusted
Then take jug with room temperature water and pour out three cups into the pot. Before placing it on the stove and heating the water to repeat the experiment, the water temperature was taken to ensure that it was approximate to the room temperature. Literature Review: According to an article in The New York Times, the notion of a body of cold water will reach boiling point quickly as to an identical body of hot water under the same parameters is false (O'Connor, 2008). In this experiment it is not to prove what has already been done, rather to find if the rise of water bodies would be parallel. The notion is to calculate the slope of increase in water temperature given two different starting points, are they both identical.
Title : Reaction of Carboxylic Acids Objective : To Determine The Reaction of Carboxylic Acids Procedure : As referred to Lab manual. Results: A. Salt Formation |Compound |Solvent |Solubility | |Benzoic Acid |Cold Water |Partially soluble | |Benzoic Acid |10 % NaOH |Soluble | B. Salt Hydrolysis Sodium acetate solution changed the color of litmus from red to blue. C. Reaction With Sodium Carbonate Observation : A lot of gas bubbles was released.
Introduction A titration was carried out in this experiment to find the concentration of hydrochloric acid is an unknown solution. The aim of this experiment is to determine the number of moles of sodium hydroxide in hydrochloric acid and then to determine the number of moles of sodium hydroxide present in gastric juices. Titration, or volumetric analysis, is a common laboratory procedure for the analysis of substances and solutions. In a titration, the analyst determines the volume of a solution, called a titrant, that reacts exactly with a known weight or volume of another substance. This reaction is carried out by adding a solution of reactant hydrochloric acid from a burette to a solution of sodium hydroxide until just sufficient of hydrochloric acid has been added to react with all of the sodium hydroxide.
In this experiment we are going to measure the solubility of KNO3 in water at various temperatures. Results can be reported in different ways ranging from grams or salt dissolving in a milliliter of water to grams of salt in 100 mL of H2O In general, systems tend to go to a state of disorder or to a state of greater entropy. During the dissolving process, the particles of the solid become randomly distributed through the solvent in sharp contrast to their orderly arrangement in the solid state. Ion the solid state there are strong forces holding these particles together. In order to dissolve the solid, energy must be expended to overcome these forces.