Water Rocket Lab Analysis

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Rocket Project Calculation/Questions/Analysis 1. Calculate the initial velocity at which it left the launch pad The ground level was zero and the height obtained was 100 m (assuming the rocket travels perpendicularly to the surface of the ground). The velocity is zero. We have three of five variables required to solve for initial velocity. V= 0 m/s – at top of apogee, the rocket has no velocity as it turns to face the ground x = 100m – the supposed height of the rocket from apogee to ground level. This was calculated using trigonometry: the angle away from launch pad and distance away from launch pad. a = -10 m/s^2 – constant acceleration of gravity Initial velocity is found using the following equation. V2=Vo2+ 2ax V is final velocity, Vo is initial velocity, a is acceleration, and x is distance. 0=Vo2+ 2-10100 Vo2=2000 Vo2=44.72 m/s Initial velocity is 44.72 meters per second. 2. Time the rocket, from launch to apogee, and confirm the height of the rocket at apogee (you may NOT use your answer for part one). There are enough factors to confirm the height of at apogee without using the initial velocity from problem one. t = 3.88 s – this was recorded from the moment the rocket was launched to apogee using a stopwatch. V= 0 m/s – at top of apogee, the rocket has no velocity as it turns to face the ground a = 10 m/s^2 – constant acceleration of gravity To calculate the height, initial velocity is determined using the following equation. V=Vo+ at V is velocity, Vo is initial velocity, a is acceleration, and t is time. 0=Vo+ -103.88 Vo=38.8 m/s To find the height at apogee: ∆x=Vot+ 12at2 x is distance from launch to apogee. ∆x=3.88(38.8)+ 12(10)(3.88)2 ∆x=75.27 m Therefore the height given in problem 1 and the time calculated in problem 2 does not match and does not confirm. 3. Draw a diagram of the rocket- label the parts and

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