Kinetic Energy Theorem

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Lab Five: Work – Kinetic Energy Theorem: W = Δ K.E. June 12, 2012 Data Table One: Work – Kinetic Energy Theorem: W = Δ K.E. T1 | T2 | V1 | V2 | KE1 | KE2 | W | 0.230 s | 0.091 s | .435 m/s | 1.11 m/s | .027 J | .240 J | 5.38 J | 0.237 s | 0.091 s | .422 m/s | 1.11 m/s | .026 J | .240 J | 5.39 J | 0.230 s | 0.091 s | .435 m/s | 1.11 m/s | .027 J | .240 J | 5.38 J | Calculations 1. V1 = d / t1 Length of the glider: 10 centimeters 10 centimeters = .1 meters .1 / 0.230 = .435 m/s 2. V2 = d / t2 Length of the glider: 10 centimeters 10 centimeters = .1 meters .1 / 0.091 = 1.11 m/s 3. KE1 = ½ MV2 The mass of the glider on a pan balance: 189.3 grams 100 grams added to the glider. Length of the glider: 10 centimeters ½ (100 g + 189.3 g / 1000) (.435)2 ½ (.289300) (.189225) .027371 J .027 J 4. KE2 = ½ MV2 The mass of the glider on a pan balance: 189.3 grams 200 grams added to the glider. Length of the glider: 10 centimeters ½ (200 g + 189.3 g / 1000) (1.11)2 ½ (.389300) (1.232100) .239828 J .240 J 5. W = ½ M (Vf 2 – Vi2 ) ½ (189.3) (.2402 - .0272) (94.650000)(.056871) 5.382840 J 5.38 J Questions 1. What force does the work? Kinetic energy is the force that does the work. 2. What are the possible sources of error in this experiment Some possible errors in experiment five: students not setting the mode of the photogate to “gate”, not turning the air blower for the track to maximum power, nor remembering the point to release the glider for each different trials (same point for each different trials). A car driving thirty miles per hour, a pitcher throwing a baseball ten miles per hour, an athlete running fifteen miles per hour, all three different

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