Drake Equation Reflection Questions

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Reflection questions about the Drake equation: Equation | Minimum values | Maximum values | R= | 1 | 7 | Fp= | 0.4 | 0.6 | Ne= | 2 | 2.5 | F1= | 0.5 | 1 | Fi= | 0.001 | 1 | Fc= | 0.5 | 0.8 | L= | 10,000 | 200,000 | N= | 2 | 1,680,000 | What value did you get for the number of civilizations? After calculating the maximum and minimum values of the equation through researching them individually, the minimum value of the Drake equation, N = R x fp x ne x f1 x fi x fc x L, was N = 2. The values were as such: * R = 1 * fp = 40 % (0.4) * ne = 2 * f1 = 50% (0.5) * fi = 0.001 * fc = 50% (0.5) * L = 10,000 (1 x 0.4 x 2 x 0.5 x 0.001 x 0.5 x 10000). These figures lead the end of the equation at the number of communicative civilizations at N = 2; meaning there is a minimum of 2 expected communicative civilizations in the galaxy. The maximum value that was proposed for the Drake equation, N = R x fp x ne x f1 x fi x fc x L, was N = 1,680,000. The values that have come to the conclusion are as such: * R = 7 * fp = 0.6 * ne =2.5 * f1 = 1 * fi = 1 * fc = 0.8 * L = 200,000 (7 x 0.6 x 2.5 x 1 x 1 x 0.8 x 200000) leaving N, the maximum number of communicative civilization to be 1,680,000. How does the value change if you double the lifetime of communicative civilizations? The value of ‘L’, the lifetime of communicating civilization and existence has been minimally estimated to 10,000, by doubling that, 20,000 the value of the number of communicative civilizations doubles to 4, only a vague rise in statistics. When the maximum value of L, (200,000) is doubled to 400,000- the number of communicative civilizations (N) changes to 336,000. The only difference is made is that the end result (N) is effectively doubled with the value of (L). How does the estimate change if we discover that

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