2A-2a/300 Week 4

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Exercise Mod 4 : 02/2015 Jason Little 1) 2 apples 1 brownie = 700 Cal. , 1 apples 4 brownie = 1400 cal 2A + B = 200 and A + 4B = 1400 Apples : 2A + B = 700 -2A – 8B = -2800 2A-2A+B-8B=700-2800 -7B = -2100 -7/-7 = -2100 / -7 B=300 BROWNIES: 2A + 300 = 700 2A= 700 – 300 2A = 400 2/2 = 400/2 A=200 There are 200 calories in the apples and 300 calories in the brownies. 2) 150 rooms total, extras cost $80 a night, w/o cost $60 a night, total rev is $10,000 x+y=150, 80(x)+60(y)=10000 x=150-y 80(150-y)+60(y)=10000 12000-80y+60(y)=10000-12000 -20(y)=2000 Y=100 X=150-100 $80(50)+$60(100)= $10,000. There are 50 $80 rooms and 100 $60 rooms 3) Find the cost to fence in 3 sides at $50 a meter the perimeter is 300M and total cost is $12,000: 2(L)+2(W)=300…show more content…
1,000 children at $2 each equals the remaining $2,000 bringing the total to $6,000. There were 1,000 adults and 1,000 Children 5) Find the sum of three nutural numbers is 15: X+y+z=15 Y=x+1 X+z=2y (x+z)+y=15 2y+y=15 3y=15 Y=5 5=x+1 X=4 4+5+z=15 Z=6 X=4.y=5,z=6 The three numbers are 4,5, and 6 6) Find the number of each ticket with a total of 180 tickets with prices at $5,$10,$15 with a total sum of $1900: $5-x, $10-y, $15z , x+y+z=180 5x+10y+15z=1900 the sum of 5 and 15 equals twice the 10 X+z=2y X+y+z=180 , 2y+y=180, 3y=180 y = 60 $10 tickets sold. 5x+10*60+15z=1900 5x+600+15z=1300/5 X+3z=260, x+z=120 120 +2z=260 , 2z=260-120 , 2z=140/2, Z= 70 $15 tickets were sold I know how many $10 and $15 tickets were sold now. With the total being $1900. 70*$15=1,050 and 60*$10=600 which brings the total to $1,650. With 1,650-1,900 = 250. 250/$5 = 50 which means there were 50 $5 tickets sold. So the Total is 70-$15 tickets, 50-$5, and 60-$10 tickets sold. 7) Find the sum of three whole numbers is 7 X , 2x=1, ( 6-3x) (6-3x)+x=(2x+1)-3 6-2x=2x-2 8=4x X=2. The three numbers are 5,2, and 0 since the only other two numbers that can be used to equal 7 would be 5 and 0 8) Eggs + Meats must be ≤ 300Mg 150e+ 100m ≤ 300 9) See attached graph file 10) See attached graph

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