D) All of the F1 progeny resembled one of the parental (P) plants, but only some of the F2 progeny did. E) none of the above Answer: D Topic: Concept 14.1 Skill: Comprehension 4) What is the difference between a monohybrid cross and a dihybrid cross? A) A monohybrid cross involves a single parent, whereas a dihybrid cross involves two parents. B) A monohybrid cross produces a single progeny, whereas a dihybrid cross produces two progeny. C) A monohybrid cross involves organisms
Generation II, child 9 and their mate (10) produced no left-handed children. This confirms that the trait skipped a generation. In generation III, child 2 and their mate (1), produced ¼ of left handed children. This shows that the parents are heterozygous for the trait because ¾ are right-handed and ¼ is left-handed. In conclusion, I learned how to create and understand a pedigree chart when focusing on a specified trait.
What is the sample space in this problem? Should the probabilities assigned to the sample space add up to 1? Explain. Geminate or not germinate. Yes they should add to 1 because those are the only outcomes.
Although the data are slightly right skewed, because of the large sample size(n=152) our inference on the mean is valid, by the Central Limit Therom. The Box Cox plot suggests a power transformation using a power, p= -0.5 would make the data more shaped like a normal distribution. The Normal Q-Q plot shows the transformed data points lying close to the straight line and the box plot of the transformed data looks symmetric with two outliers. The numerical summary of the transformed data confirms that the transformed data are symmetric (mean=1 and median=1). A Shapiro-Wilk test on the transformed data provides no evidence against the transformed data having come fro a normal distribution (P-value=0.4286).
These are the only possibilities. isometric drawing Finding the Answer orthographic drawing 5. Are there other nets that have three or four triangles that share an edge with the square base? Explain. No; any other such net can be superimposed on one of the nets from Step 3 by a flip or a rotation.
1. A random sample of size 15 is selected from a normal population. The population standard deviation is unknown. Assume the null hypothesis indicates a two-tailed test and the researcher decided to use the 0.10 significance level. For what values of t will the null hypothesis not be rejected?
1. A random sample of size 15 is selected from a normal population. The population standard deviation is unknown. Assume the null hypothesis indicates a two-tailed test and the researcher decided to use the 0.10 significance level. For what values of t will the null hypothesis not be rejected?
Math 1600 Basic Probability and Statistics In this word document you have one example of what is expected when you have to compute the mean and the variance of a discrete probability distribution In page number 3 you have the modified exercise 4 for quiz No 8 Example 1. | Defective Transistors From past experience, a company has found that in cartons of transistors, 92% contain no defective transistors, 3% contain one defective transistor, 3% contain two defective transistors, and 2% contain three defective transistors.Find the mean, variance, and standard deviation for the defective transistors. Construct the probability histogramSolutionFill in the values in the table below
When they are given the X chromosome with a mutated gene for hemophilia and are female, they will have one functioning clotting gene and will have little to no manifestations of hemophilia. A male given the mutated X chromosome for hemophilia will only have the mutated gene and will have one of many varying expressions of hemophilia. Based on a percentage range of clotting factors (factor VIII for hemophilia A and factor IX for hemophilia B), a patient can have mild hemophilia (6-50%), moderate hemophilia (1-5%), or severe hemophilia (< 1%). While decreased levels of factors in the clotting cascade do not cause the patient to bleed faster, they do cause prolonged coagulation. It is easy to confuse bleeding disorders with clotting disorders.
Only two items showed a significant difference on the WISC R, and one was dropped from the WISC III. For the WAIS III items were given to AA, Hispanic, and White people and any items not answered equally by all three groups were dropped. Thus, there were no items on the test that differentiated between blacks and white prior to its