AB is the diameter of a circle. A is (1, 3) and B is (7, -1). i) Find the coordinates of the centre C of the circle. [2] ii) Find the radius of the circle. [2] iii) Find the equation of the circle.
B. C. D. Square Regular hexagon Regular pentagon Equilateral triangle MA.912.G. 6.6 5. Which is the equation of the circle shown below? A. B. C. D. MA.912.G.7.5 6.
8 5 7 8 (a) 7 7 8 6 6 11 7 5 5 7 9 9 6 7 6 7 Construct a frequency table from the above data and add a cumulative frequency column. For this data, find: (i) the median; (ii) the lower quartile; (iii) the upper quartile. 2 (b) 1 1 1 2 (c) Construct a boxplot for this data. [Turn over [ X100/201] Page three Marks 3. The diagram below represents a sphere.
E. distorted tetrahedron (seesaw). 61. According to VSEPR theory, which one of the following molecules is trigonal bipyramidal? A. SF4 B. XeF4 C. NF3 D. SF6 E. PF5 62. Which one of the following molecules has tetrahedral geometry?
What value will be stored in result in each of the following statements? a) 12 = x + y b) 4 = z * 2 c) 2 = y / x d) 6 = y – z 5. Write a pseudocode statement that declares the variable cost so it can hold a real numbers. Dim cost1 As Double = 0 6. Write pseudocode statement that declares the variable total so it can hold integers.
Show the steps of conversion that you used. Adding leading zeroes creates the number 001101102 which can be split into 00112 and 01102 the hexadecimal value for these two bytes are 316 and 616 respectively so this number would be 3616 Exercise 1.3.6 Represent the hexadecimal value f616 in binary and decimal. Show the steps of conversion that you used. F16 = 11112 and 616 = 01102 when put together the binary value is 111101102 which is equal to 246. Lab 1.3 review 1.
Set up the matrix equation to solve this system. 2. Given the inequality y < x2 + 2x – 3, is the point (0, -3) part of the solution? Name a point that is part of the solution and one that is not. 3.
The distance between the forces is given by the Coulombs law through the use of the formula F=kq1q2/r2.0.1newtons = 8.99*109*3.2*10-6*7.7*10-7/r2 R= 555.78 Answer to question 3 • Potential difference between the two plates is equal to velocity which is equal to 6.0*106m/s • Force = mass *acceleration = 1.4*10-13*6.0*106 = -8254 nektons The speed of the particles are computed by the formula V=ED. This is equal to 8.5*10-6*0.15. This is equal to 84.1 Answer to question 4 Voltage = current *resistance. This implies that in this case while V is 5.0 and resistance is 1.0*103, current will be equal to 5/1.0*103, = 500 amps B the direction of the conventional current provides the electric charge movement from the positive side of the battery to its negative side as in indicated in the diagram below Answer to question 5 • This section focuses on the equivalent resistance of a circuit. The equivalent resistance will be equal to (5.0*102+1.00*103)2.
Procedure: Part I: Rectangular Solid (Wooden Block) Mass: In order to find the mass of the rectangular solid utilize the balance.Document the mass by rounding to the closest 0.1 g in the data table underneath. Volume: Find out the length, width, and height of the rectangular solid by utilizing the metric ruler. Document these by rounding to the closest 0.01 cm. Utilize the formula for
Using the Pythagorean Theorem, solve for the missing sides. ____________10) ___________ 11) Find the value of x and y in each special right triangle. Give final answers in most simplified form. 12) x = _____y = _______ 13) x = ______y = ______ 14) x = _____y = _______ REGULAR POLYGONS 15) Given a hexagon with apothem length of [pic]cm. Determine the following.