Unit 8 Assignment 1 Answer Key

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Completed on Sunday, 15 April 2012, 07:19 PM Time taken 53 mins 56 secs Marks 7/12 Grade 6 out of a maximum of 10 (58%) Question 1 Marks: 3.0 Given: The bottom motor starts first, and the top motor starts up after the bottom motor reaches full speed, and the client has no specific time delays in mind for the most downstream relays. Also the TMS steps available range from 0.05pu to 1pu in steps of 0.05pu. Calculate the Plug Bridge Settings for Ctop and C bottom: Choose one answer. A. PBS Ctop = 0.5 pu, PBS Cbot = 0.5 pu B. PBS Ctop = 1.25 pu, PBS Cbot = 1.0 pu Correct well done! C. PBS Ctop = 1.25pu, PBS Cbot = 1.25 pu D. PBS Ctop = 1.0 pu, PBS Cbot = 1.0 pu The most important thing to get this section correct is the correct calculation of I start from the given motor…show more content…
Choose one answer. A. 0.26 pu B. 0.25 pu C. 0.3 pu Correct, well done! D. 0.24 pu This relay TMS is often only wrongly calculated if errors were made on the settings of the other downstream relays. However, assuming the other relays are correctly set, beware to note the next available step of the TMS is required and to note the steps whether they are every 0.01pu or every 0.05pu. Correct Marks for this submission: 1.0/1.0.Question 7 Marks: 1.0 Now calculate the response time of Relay A for a fault current of 8075 A. Choose one answer. A. 0.985 s B. Cannot be calculated as the current is less than 8500A Think! The relay must provide back up to relay B for a fault smaller than 8500A occurring on feeder BC. C. 0.853 s D. 0.925 s Don't panic. Use the calculated settings for Relay A, and calculate the response time of relay A for a fault current of 8075A. i.e. PSM=8075/(ES A), then get t(TSM=1pu), then multiply this time by the set TMS A to get the required response time of relay

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