When an object demonstrates a constant acceleration, the velocity of the object will change either increasing or decreasing with the same rate while traveling in the same direction. During this experiment, we used the equationH=12gt2 . From this equation, h denotes height, g represents acceleration due to gravity (9.8 m/s2), and t stands for time. The variables in this equation are all accounted for with the exception of g. The height is the distance from the bottom of the ball to the top of the pad (measured in meters). The time (t) corresponds to how long it took the ball to travel after being released from the clip to the pad
Oscillations of a Mass - Spring System Determination of “K” by the use of a Spring Oscillations System Experiment #3 for AMS320 involves a spring oscillating system to determine the value of “K”, the force value of an oscillating spring system. The spring is secured to a solid point and allowed to hang vertically below the solid stand. On the bottom of the spring is attached a steel ring with in which to attach a known amount of weight in (kg). The weights are added to the ring and the spring is pulled into a small amount of tension and released. The spring will then oscillate up and down and a stopwatch will be used to measure the amount of time it takes the weight and spring system to stretch and recoil ten times.
The spring represents the elastic components of the muscle and obeys Hook’s law : F=k*x but in terms of stress the equation turns into : σ=Ε*ε where σ: applied stress, E:Young's Modulus of the material ε: strain. The dashpot represents the viscous components of the muscle and is expressed in differential form by Newton’s law for straight,parallel and uniform flow: σ=η* where η: viscosity and :change of rate of strain (velocity). The important equations that are used in this model are: F=F1+F0 where F0=k0*u and F1=η1*u1=k1*u1’ u=u1+u1’ After long calculations we finally take the differential equation of motion for a standard linear solid: The equation contains F, df/dt ,u ,du/dt functions as well as k0,k1,η constants and is impossible to solve as they are all unknown. For that reason we will use the experimental data from Bobsbooms given paper that will help understand how our functions are supposed to behave during the experiment and thus be able to extract some data and some important initial and boundary conditions, necessary for our model to work. From the Bobsbooms paper ‘Passive transverse mechanical properties of skeletal muscle in compression’ we are supposed to take the ramp and hold data (u versus t graph) and fit it in our model,expecting that our F versus t
Hookes Spring Experiment Pashin Research question: How the force applied to a spring affects extension of the spring? (F=-kx) Variables: Independent variable: Different Mass Dependent variable: The Displacement of the spring Controlled variable: Spring Material: 1. Spring 2. Masses a. 50 b.
We used a vernier caliper to obtain the diameter of those two and therefore, the radius. When adding all the numbers together, we found that the true radius(r) of the orbit was 0.139 m. To find our tension, we needed to find out how much weight we needed to pull the object towards away from the spring and on the tip of the pointer as shown below. The tension needed to pull the mass on the tip of the pointer 1.05 kg. In theory the force of acceleration needed to pull the mass to same exact spot should equal the force of tension multiplied by the force due to gravity. Using Newton’s second law, F=ma, we know that the
Newton’s Second Law Lab Purpose: The purpose of this experiment was to determine the relationships between mass, force and acceleration as well as to prove Newton’s second law Hypothesis: It was hypothesized that there would be an inverse relationship between acceleration and mass; as the value of the mass increased the acceleration decreased. As well it is hypothesized that there would be a direct relationship between the net force and acceleration; as the net force increases the acceleration increases as well. Materials & Method: The materials that were required to do the experiment were a metre stick; its purpose was to measure the amount of string that is going to be used to drag the cart. Next equipment needed for the lab was a dynamic cart; it was going to be dragged by the string with a mass on the other end and will find relationships between these two. Also string (about 75cm) was needed in this experiment which would help pull the cart with the help of the masses that were used.
1 of 22 Investigation of Deflection of a Cantilever vs. Length of a Cantilever Research Question How does the length of a cantilever affect the deflection of that cantilever when loaded with a constant mass? Introduction The purpose of this lab is to investigate the deflection of a cantilever. In this investigation, I chose to measure the effect of the length of a cantilever on its deflection when loaded with a constant mass because I knew from prior experience that there was some relationship between the two variables. The objective of this investigation is therefore to establish a relationship between the length of a cantilever and its deflection in the aforementioned situation, which may give some insight into the physics of cantilevers.
In order to use the principles of fluid statics to analyze pressure in a system, it is helpful to make several assumptions. Fluids are assumed to be incompressible, in other words, they occupy a constant volume and maintain a constant density throughout the experiment. Pressure on a fluid at rest is assumed to be isotropic at every point, which is necessary to satisfy the zero sum force balance at a given point. In addition, pressure is assumed to be exerted normal to the contact surfaces at the boundaries of the system. Pressure in a given system is governed by the following equation: P = ρgh = γh (Eq.
The direction of acceleration is the same as the direction of the net force. The acceleration of the body is also directly proportional to the net force but inversely proportional to its mass. Newton defined momentum P as the product of mass and velocity. The change in momentum, symbolized by ∆P, is brought about by the impulse acting on the body, F_net ∆t=∆P As ∆t approaches zero, the instantaneous rate of change of momentum is, F_net=lim┬(∆t→0)〖∆P/∆t〗=dP/dt=(d(mv))/dt Since for most object, mass is constant, F_net=m dv/dt Newton’s second law of motion is mathematically expressed as F_net=ma From Newton’s second law T=m_1 a The hanging mass m_1 is also accelerating with the same acceleration due to the net force m_2 a on it. m_2 a=m_2 g-T T=m_2 g-m_2 a Equating the tensions m_1 a=m_2 g-m_2 a m_1 a+m_2 a=m_2 g (m_1+m_2 )a=m_2 g a=(m_2 g)/(m_1+m_2 ) The acceleration is the same acceleration described in the kinematics equation a=2s/t^2 For a body starting from rest, s is the distance traveled by the cart and t is the time of travel.
e always obtainedan unreasonable value of height that's why we keep on repeating the trial. -o minimie sucherror, the experimenter pulling the spring balance must ensure that the force exerted is horiontalto ensure low percentage error. Conclusion: ork is defined mathematically by the dot product of the vector 5orce F anddisplacement. &lso, /ower is defined as the ratio of work and time. In part 1 of the experiment,the data obtained can show that ork is somehow related to /ower.