Specific Heat Capacity:

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Specific Heat Capacity: Background Information: Specific Heat capacity is the quantity of heat required to raise the temperature of unit of mass of a substance by a unit changes in temperature. Theory: The equation we are using for the experiment VI∆t = mc∆T VI∆t: Energy supplied by heater mc∆T: Energy received by aluminum block Trial 1 (Aluminum Metal Block) | Potential Energy (± 0.01V) | Current(± 0.001 A) | Time(± 1 sec) | Mass(± 0.001 kg) | Temperature(± 0.1 K) | 6.71 | 1.994 | 60 | 1.000 | 298.9 | | | 120 | 1.000 | 299.1 | | | 180 | 1.000 | 299.9 | | | 240 | 1.000 | 300.1 | | | 300 | 1.000 | 301.0 | | | 360 | 1.000 | 301.2 | | | 420 | 1.000 | 301.8 | | | 480 | 1.000 | 302.2 | | | 540 | 1.000 | 302.7 | | | 600 | 1.000 | 303.0 | 6.72 | 1.993 | 660 | 1.000 | 303.5 | Avg≈6.72 | Avg≈1.994 | | | | Trial 2 (Aluminum Block) | Potential Energy (± 0.01V) | Current(± 0.001 A) | Time(± 1 sec) | Mass(± 0.001 kg) | Temperature(± 0.1 K) | 6.79 | 1.991 | 60 | 1.000 | 301.4 | | | 120 | 1.000 | 302.0 | | | 180 | 1.000 | 302.6 | | | 240 | 1.000 | 303.0 | | | 300 | 1.000 | 303.6 | | | 360 | 1.000 | 304.0 | | | 420 | 1.000 | 304.3 | | | 480 | 1.000 | 304.9 | | | 540 | 1.000 | 305.1 | | | 600 | 1.000 | 305.8 | 6.77 | 1.994 | 660 | 1.000 | 306.0 | Avg=6.78 | Avg= 1.992 | | | | DATA for Aluminum Metal Calculation of the Aluminum Metal Block: The equation of the experiment in order to find the specific heat capacity is VI∆t = mc∆T Or SHC (c) = VIm(∆t∆T) By the look of the graph of the Aluminum Block the ∆t∆T is equal to inverse of gradient of the line that is ∆T∆t. Since we know some of the information we have found out we will able to solve it: VA = 6.75, IA = 1.994, m= 1.000, ∆T∆t = (0.007879)-1 ≈126.92 from Trial 1, SHC1 = 6.75 (1.994)1.000 (126.92) =

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