Solve the triangle. Given: A = 48° C = 97° a = 12 B = 35° b = 9.2 c = 16.0 5. The given measurements produce one triangle. Given: a = 7, b = 5, A = 70° C = 67.8, B = 42.1, c = 6.8 6. x×tan62 = (x+300)×tan53 = perpendicular x = 300×tan53/(tan62-tan53) = 719.0295 yards AB = (x+300/cos53 = 1019.0295/cos53 = 1693.3 yards Distance between A and B is 1693.3 yards 7. Given: sides, 5,6,7 in miles Island A = 78.46° Island B = 135.58° Island C = 57.12° Given the information… From Island B I would travel a Northwest Bearing to Island C. 8.
The average needle length varied from between 98.93 mm to 129.77 mm. The minimum needle length was measured on tree 5 and was 55 mm. The maximum needle length was measured on tree 7 and was 167 mm. The standard deviation ranged between 14.20 to 21.59 mm. More detailed data can be found in Table 1.1.
II. Materials: a. 1.5m nylon cord b. 2-hole rubber stopper c. masking tape d. meter stick e. PVC tube, about 15cm long and 1cm in diameter f. set of different masses g. stopwatch III. Data Table #1 Trial Mass of Stopper Hanging Mass Radius T1 T2 T3 Revolutions 1 0.014kg 0.05 kg 0.595m 12.93s 13.10s 14.6s 20 2 0.014kg 0.1 kg 0.595m 11.53s 11.78s 10.8s 20 3 0.014kg 0.15 kg 0.595m 8.59s 9.37s 9.35s 20 4 0.014kg 0.2 kg 0.595m 8.0s 8.03s 7.72s 20 5 0.014kg 0.1 kg 0.765m 12.97s 13.81 ------- 20 6 0.014kg 0.1 kg 0.50m 10.78s 9.72s ------- 20 7 0.014kg 0.1 kg 0.60m 10.0s 10.25s ------- 20 *For the last 3 trials, we only had time to take 2 time intervals.
48 – 23 is less than 43 – 28. B. 48 – 23 is greater than 43 – 28. C. 48 – 23 is equal to 43 – 28. What fraction of the shapes below are circles?
BMI=xKG/ym*ym the formula. x=body weight in kilograms y= body height in meter. June 2013 Body Mass Index 3 132 Divide your weight and one kilogram equals 2.2lbs. 2.2= 60 kg (60*0.254) (60/1.52) (39.47 *1.52) Multiple 60 Kilograms and 1 inch equals 0.254 meters. BMI=25.96 this is what I came up with as my BMI figure in the Kg/Meters.
Ozark Furniture Inequalities Jason Campbell Math 221 Instructor Laura Cella 02/09/2014 Ozark Furniture Inequalities For the purpose of this paper, I will attempt to solve problem 46 in the text “Elementary and Intermediate Algebra, 4th Ed.” The problem states, “Ozark Furniture Company can obtain at most 3000 board feet of maple lumber for making its classic and modern maple rocking chairs. A classic maple rocker requires 15 board feet of maple, and a modern rocker requires 12 board feet of maple. Write an inequality that limits the possible number of maple rockers of each type that can be made, and graph the inequality in the first quadrant.” (Dugopolski, N/D) Though to be honest, I think more along the lines of having “Classic Rockers” be Sammy Haggar, and the “Modern Rockers” to be like Velvet Revolver. However, for this, we have to use chairs, more is the pity. Using this text for the first set, namely classic chairs, I will take the variables and plug them into an equation.
Refer to figure ten, the white pine (Ps) was dominant 100 years ago rather then the hemlock (Ts) and black birch (Bl) which are dominant now. And the only two species in the understory were exclusively hemlock and beech (Fg), rather then having a more diverse population of species as we have now of beech, red oak (Qr), red maple (Ar), White pine, sugar maple (As), Yellow birch (Ba) and hophornbeam (Ov). The rest of the species were either not present or at very low quantities, such as the white ash (Fa) is now. 6. As discussed
A.A.44: Using Trigonometry to Find a Side: Find the measure of a side of a right triangle, given an acute angle and the length of another side 1 In the accompanying diagram of right triangle ABC, [pic] and [pic]. [pic] Which single function could be used to find AB? |1) |[pic] | |2) |[pic] | |3) |[pic] | |4) |[pic] | 2 In right triangle ABC, [pic]. Which equation is true for this triangle? [pic] |1) |[pic] | |2) |[pic] | |3) |[pic] | |4) |[pic] | 3 The accompanying diagram shows a ramp 30 feet long leaning against a wall at a construction site.
The demensions are a base of 30.9m by 69.5m. The Parthenon featured an octastyle, or 8 column arrangement at both narrow ends, with 17 columns along the wider sides. The architects used the common ratio of 9:4 for the side columns and for the spaces between the columns, although strayed from strict geometric principles for design purposes like the columns’ slight curving upward toward the cella, and a bowing in the floor, raising the centre about four inches higher than either end. This made the Parthenon appear straight from a distance. The octastyle façade, capped with a triglyph, is comparable to the entrance design of the Pantheon built by Hadrian, who was said to be a big fan of Greek architecture.
Answer the next four questions using the following set of numbers. Show your work for all questions: 2.0, 3.7, 4.9, 5.0, 5.7, 6.7, 8.5, 9.0 What is the range of the above values? Range is the difference between the lowest value and the highest value. The range of the listed numbers is 9.0-2.0=7.0. What is the median of the above values?