Daniel Jones NT1210 Lab 1.1 Review 1. Convert the decimal value 127 into binary. Explain the process of conversion that you used. 127 | 127 | 63 | 31 | 15 | 7 | 3 | 1 | 128 | - 64 | - 32 | - 16 | - 8 | - 4 | - 2 | - 1 | | = 63 | = 31 | = 15 | = 7 | = 3 | = 1 | = 0 | 0 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | The answer is: 01111111 If the decimal number is less than the greatest power of 2 than you must put a 0 for that number than carry that same decimal number over to the right one decimal place. For example.
If you were to take the three trigonometric functions of the 30 degree angle, you would get the (square root of 3)/2 for cosine, ½ for sine and the (square root of 3)/3 for tangent. If you were to take the three trigonometric functions of the 60 degree angle, you would get ½ for cosine, the (square root of 3)/2 for sine and the square root of 3 for tangent. 3) Suppose that you did not have the Unit Circle on Circle A, but rather of a circle of radius 5. Will the angle measures in degrees and/or radians change? Why or why not?
o D. The mass is not exactly 255.0 grams, but it is impossible to tell whether the mass is greater than or less than 255.0 grams. 5. 5. You place a mass of 250 grams on the measurement tray of a triple beam balance and then set the rider on the 500 gram beam to the 200 gram mark (the other riders are set to 0 grams). Which of the following statements is true?
TOPIC 8 Chi-Square goodness-of-fit test Problem 12.1 Use a chi-square goodness-of-fit to determine whether the observed frequencies are distributed the same as the expected frequencies (α = .05) Category | fo | fe | 1 | 53 | 68 | 2 | 37 | 42 | 3 | 32 | 33 | 4 | 28 | 22 | 5 | 18 | 10 | 6 | 15 | 8 | Step 1 Ho: The observed frequencies are distributed the same as the expected frequencies Ha: The observed frequencies are not distributed the same as the expected frequencies Step 2 df = k – m – 1 Step 3 α = 0.05 x 2 0.05, 5df = 11.0705 Step 4 Reject Ho if x 2 > 11.0705 Category | fo | fe | | 1 | 53 | 68 | | 2 | 37 | 42 | | 3 | 32 | 33 | | 4 | 28 | 22 | | 5 | 18 | 10 | | 6 | 15 | 8
80 × 2 = 160 160 × 2 = 320 320 × 2 = 640 The next three terms of the sequence are 160, 320, and 640. 6. 100, 50, 25, … SOLUTION: Calculate common ratio. The common ratio is 0.5. Multiply each term by the common ratio to find the next three terms.
Practice Test 4 –Bus 2023 Directions: For each question find the answer that is the best solution provided. There is only one correct answer. 1. For a sample size of 30, changing from using the standard normal distribution to using the t distribution in a hypothesis test, a. will result in the rejection region being smaller b. will result in the rejection region being larger c. would have no effect on the rejection region d. Not enough information is given to answer this question. ANSWER: a -recall that all the t-values are larger than the z-values so it makes it more difficult to reject the null.
Problem #35 • This sequence is arithmetic • The cost to build the tower is $1800. STEPS/CALCULTATIONS YOU PERFORMED TO REACH THE ANSWER: The common difference in this sequence is $25, thus making it an arithmetic sequence. The formula for finding the final term is an = a1 + (n-1)d. In this problem, n=9 for the 9 sections of 10 foot sections, a1=100 since that is the first term of the sequence, and d=25 for the common difference. An = a1 + (n-1)d A9 = 100 + (9-1)25 A9 = 100 + (8)25 A9 = 100 + 200 A9 = 300 So the final term of the sequence is 300. Now that we know this, we can find the sum of the terms to calculate the final cost.
Here is how we think about it: It is $100 for the first 10 feet. After that it is $25 for each additional 10 feet. This tells us that it is arithmetic sequence because we are multiplying. N= the number of terms altogether N= 8 D= the common difference D=25 A1= the first term A1= 100 An= the second term An= a8 Next, we need to compute what a8 is. An= a8+ (n-1) d A8= 100+ (8-1)25 A8=100+7(25) A8=100+200 A8=300 Now that we know what A8 is, we need to know what the sum of the sequence is from A1 to A8.
23(5329)703<W< 25(5329)703 After I multiply I end up with 122567703<W< 133225703 Then I simply divide and end up with 174 < W < 189.5. So people who are 73 inches tall that way between 174 and 189.5 are probably not overweight. Now for the third equation I will use 25 and 30 in place of 23 and 25 in the above equation. 25(5329)703<W< 30(5329)703 Then I will multiply the parentheses. 133225703<W< 159870703 Then I must do the division.
25x2 – 300x = 0 Factor the left side. 25x(x – 12) = 0 Use Zero Factor Property 25x = 0 or x -12 = 0 Solve each equation. x = 0 or x = 12 The parabola will cross the x-axis at 0 and 50. This quadratic function has a large a value which means the parabola will be narrow. It also has a negative a value so the parabola will open downward.