The relationship between Hamstring strength index 60 degree/s and the Shuttle run test is a negative relationship due to r moves away from zero in negative direction and r = −0.149, the strength of this negative relationships would be weak with r -0.5 r=-0.528**, is more significant since p =0.002< 0.01, where r = −0.498** is significant at p =0.004< 0.01. The smaller the p-value in a test of hypothesis the more significant the results are. 8. The researchers stated that the study showed a positive, significant correlation between Quadriceps strength indices and pre- and postoperative functional stability Considering the data presented in the Table 5, do you agree with their statement? Provide a rationale for your answer.
$500 (= $25 ´ 20 radios not stolen due to hiring 1 guard) c. 4 Chapter 4 Applied Problem 1. a. The intercept a is expected to be positive because even if no advertising is undertaken, some sales are expected to occur. b is expected to have a positive sign since Vanguard's sales are positively related to its level of advertising expenditures. Vanguard's sales should be inversely related to its rivals' expenditures on advertising, so c is expected to be negative. b. a is the sales of Bright Side detergent when neither Vanguard nor its rivals advertise.
The coefficient of correlation is given as r = 0.752843. The positive sign of the correlation coefficient indicates a positive or direct
It is reasonable to set the value to 0 because if one makes the value 0 we can observe a more precise answer, than if one changes the intercept. When I changed the intercept to 1 the equation decreased and had a +1 to it. It slowly kept decreasing as I increased the number. 6) Compare the equation of the line of best fit for your random sample with the lines
5. A test statistic is a value determined from sample information used to reject or not reject the null hypothesis. 6. The region or area of rejection defines the location of all those values that are so large or so small that the probability of their occurrence under a true null hypothesis is rather remote. 7.
It has a medium heat yeild and the burn difficulty is easy. It is hard to split. It produces light smoke and no spark. It produces 19.1 million btu's per cord. I found that cherry has a good rating for burning.
When comparing the variables: RACE and XMARSEX, many conclusions arise. The contingency coefficient is: .070. This indicates a weak, positive relationship between the variables. This means that race has little impact on a person’s opinion about having sex with a person other than a spouse. The approximate sig is: .000.
The Heteroskedasticity Problem in Regression Analysis Recall that one of the assumptions of the OLS method is that the variance of the error term is the same for all individuals in the population under study. Heteroskedasticity occurs when the variance of the error term is NOT the same for all individuals in the population. Heteroskedasticity occurs more often in cross-section datasets than in time-series datasets. Consequences of Heteroskedasticity: 1. the estimates of the b’s are still unbiased if heteroskedasticity is present (and that’s good), 2. but, the s.e.’s of the b’s will be biased, and we don’t know whether they will be biased upward or downward, so we could make incorrect conclusions about whether the X’s affect Y 3. the estimate of S.E.R. is biased, so we could make incorrect conclusions about model fit Detecting Heteroskedasticity: 1.
It must contain at least a certain number of observations C. It refers to descriptive statistics D. All of the above are correct 4. Which of the following is not a reason for sampling? A. The destructive nature of certain tests B. The physically impossibility of checking all the items in the population C. The adequacy of sample results D. All the above are reasons for sampling 5.
The Hardy-Weinberg Law states that the genotype frequencies of a population will remain in equilibrium, given that the population size is infinitely large and randomly mating. Migration, mutation, selection and genetic drift are also assumed to be absent. Mathematically, if the frequency of an allele (A) is p and the frequency of another allele (a) is q (p+q = 1), the genotypic ratio of AA:Aa:aa in the following generations will remain in the ratio p2:2pq:q2 (p2+2pq+q2 = 1). This ratio is known as the Hardy-Weinberg equilibrium. In reality, it is very unlikely that the above criteria are all met in a population, but the Hardy-Weinberg equilibrium is still useful as it functions as a null hypothesis.