Part B: Density of a Cylindrical Solid 1) Obtain a cylindrical solid and measure its mass. 2) Measure diameter and divide by 2 for the radius, and measure height. 3) Determine the volume by means of πr2h. 4) Determine the density and percent error. Part C: Density of an Irregular Shaped Solid 1) Obtain a sample of metal and determine the mass.
328.0 grams o C. 439.0 grams o D. 48000 grams 4. 4. Based on the image, what can you infer about the mass of the object being measured? o A. The mass is exactly 255.0 grams.
How is finding volume different from finding area? d. If you had cubes with a length of 1 centimeter, how many would you need to build the cube in the picture above? Calculating volume of a rectangular prism Rectangular prisms are like cubes, except not all of the sides are equal. A shoebox is a rectangular prism. You can find the volume of a rectangular prism using the same formula given above (V= l × w × h.) Another way to say it is to multiply the area of the base times the height.
Warm up questions: Exercise1： mass of ZnI2 is 2.56g The molar mass of ZnI2 is 319.18 g/mol The mole of ZnI2: 2.56g/319.18g/mol=0.00802mol 0.00802mol/(500*10-3L)=0.01604M 0.01604M ZnI2 should appear on the label of the flask. Exercise 2: Student 1: 0.43g zinc iodide The mole of ZnI2: 0.43g/319.18 g/mol= 0.00135mol 0.00135mol/0.01604M=0.084L 0.084L*(1000mL/1L)=84mL Student 2: 5.0*10-4 moles of zinc iodide. 5.0*10-4mole/0.01604M=0.031L 0.031L*(1000mL/1L)=31mL Molarity as a Concentration Unit Exercise 3: a. 2.56g ZnI2/500 mL of solution 2.56g/319.18 g/mol=0.00802mol 0.00802mol/(500*10-3L)=0.016M b. 0.00512g ZnI2/mL of solution 0.00512g/319.18 g/mol=1.6*10-5 mol 1.6*10-5 mol/(1*10-3L)=0.016M c. 0.00806 moles of ZnI2/500 mL of solution 0.00806mol/(500*10-3)L=0.016M d. 0.0161 moles of ZnI2/L of solution 0.0161mol/1L=0.016M Exercise 4: a.
On page 29 is the explanation of uncertainty. The concept is illustrated in Figure 13 on page 30. I expect your report will include length to 0.1 cm, a whole mm, and to 0.001 m. As an example, a sheet of paper is 21.6 cm, 216 mm, or 0.216 m wide. In each case, the measurement is precise to 1 mm (which is 0.1 cm and 0.001 m). The first degree of uncertainty is at the mm length.
Dimensional analysis and use of conversion factors in calculations. * Equalities and prefixes involving relationships on Table 1.5 (page 14), and between the following units: Angstrom (Å) and m; g and µg; g and mg; g and kg; ml and µl; ml and L; cm and m; cm and km; in and cm; in and m. * Measurement and calculations involving with Density and Specific Gravity of a substance (Density is mass per unit volume of a substance: d
NaOH (aq) + KHP (aq) —› Na+ (aq) + K + (aq) + P2- (aq) + H2O (l) NaOH (aq) + CH3COOH (aq) —› Na+ (aq) + CH3COO- (aq) + H2O (l) The titration of NaOH with KHP will identify the concentration of the NaOH provided. KHP will be weighed and its mass will be recorded. The moles of KHP will be calculated: Moles KHP = Mass KHP recorded / Molar mass of KHP = Mass of KHP recorded / 204.22g/mol The volume of NaOH will be determined by reading the
Can be used to represent one character in the lowercase English alphabet c. Represents one binary digit d. Represents four binary digits 2. Which of the following terms means approximately 106 bytes? a. Terabyte b. Megabyte c. Gigabyte d. Kilobyte 3. Which answer lists the correct number of bits associated with each term? a.
There are two types of special right triangles: 45-45-90 and 30-60-90. The legs on a 45-45-90 triangle are 1 and 1 and the hypotenuse is the square root of 2. The legs on a 30-60-90 triangle are 1 and the square root of 3 and the hypotenuse is 2. If you were to take the three trigonometric functions of either 45 degree angle, you would get the (square root of 2)/2 for both cosine (x) and sine (y) and 1 for tangent (y/x). If you were to take the three trigonometric functions of the 30 degree angle, you would get the (square root of 3)/2 for cosine, ½ for sine and the (square root of 3)/3 for tangent.
Measurements of the radius and length of the cylinder provided its volume and theoretical density of 2.74 g/cm^3 which confirmed Archimedes’ Principle. The principle was further confirmed by calculating a 2.99% difference between the buoyant force and the weight of the aluminum cylinder. In the second part, a 30.5 g wooden cylinder was hung from a string and attached to a scale and lowered into the water-filled graduated cylinder as much as could be submerged with the string remaining taut. The wood displaced approximately 12 mLs of water and had an “apparent mass” of 20 g while