The hypothesis of this experiment goes as follows, If we place potato cells in a salt solution, then the cells will shrink. They will shrink because when the salt is added the water in the potato, where there is high concentration, will move to the outside of the potato where there is low concentration.
If we place the potato in a sucrose solution with a similar solute concentration as a potato, then the least amount of water will diffuse into or out of the potato cells. This occurs because this scenario will be initially closest to an isotonic solution, allowing us to determine the solute concentration of a potato. Materials: * Knife/ Cork Borer * Seven 30 cm pieces of Dialysis tubing * Thirteen 250 mL Beakers * 15% Glucose Solution * Glucose Test Strips * 1% Starch Solution * Distilled water * Lugol’s solution * 25 mL of: * .2 M sucrose * .4 M sucrose * .6 M sucrose * .8 M sucrose * 1 M sucrose * Paper Towels * Clock * Potatoes * Plastic
Effect of Surface Area to Volume Ratio on Diffusion Rate of Glucose from Potatoes Abstract: The experiment was conducted to determine if differences in surface area had a significant effect on diffusion rate of glucose from potatoes. Potato samples of three different lengths were collected through a process of coring along the middle of the vegetable. Cores were soaked in distilled water for a period before an o-dianisidine-enzyme solution was added. Glucose diffusion rates were determined by using a spectrometer after a period of incubation of the potato samples. Glucose levels were measured at 0.52, 0.57, and 0.67 showing that an increase in surface area corresponded with a non-significant (p=0.096) increase in the glucose diffusion rate.
Be sure to report the correct number of significant figures and unit for each measurement. (Use the exponent for 0C) Be sure to record the mass to +/- 0.1 g and the temperature to +/- 0.1 oC. Table #1 Food Item Description Marshmallow Peanut / Walnut Other Sample-Identify 1 Mass of food & holder 1.2g 0.8g 0.8g 2 Mass holder 0.6g 0.5g 0.3g 3** Mass of food (subtract 2 from 1) (before burning) 0.6 g 0.3g 0.5g 4 Mass of food & holder – initial (same as 1) 1.2g 0.8g 0.8g 5 Mass of food & holder – after 0.6 g 0.7g 0.4g 6 Mass of food burnt (subtract 5 from 4) 0.6 g 0.1g 0.4g 7 Mass of beaker & water 110.1 110.1 110.1g 8 Mass of beaker 66.9g 66.9g 66.9g 9 Mass of
Mexico - Taqueria Style Tacos! Ingredients: 3 pounds flank steak 1/3 cup white vinegar 1/2 cup soy sauce 4 cloves garlic, minced 2 limes, juiced 1/2 cup olive oil 1 teaspoon salt 1 teaspoon ground black pepper 1 teaspoon ground white pepper 1 teaspoon garlic powder 1 teaspoon chili powder 1 teaspoon dried oregano 1 teaspoon ground cumin 1 teaspoon paprika 1 white onion, chopped 1/2 cup chopped fresh cilantro 1 lime, juiced 2 large tomatoes, chopped 2 jalapeno peppers, chopped 1 white onion, quartered 4 cloves garlic, peeled 4 dried New Mexico chile pods 1 pinch salt and pepper to taste 1 (32 ounce) package corn tortillas 2 cups grated cotija cheese (optional) 2 limes, cut into wedges Method: Step 1. Lay the
2.Place all ingredients in a large bowl and mix well. 3.Pour the mixture in greased casserole dish. 4.Bake for 25 minutes. Serves: 3 Serving size: 2 cups Nutritional analysis (per serving): 790 calories 67 g protein 38 g fat 3440 mg sodium 457 mg calcium Note: Nutritional analysis may vary depending on ingredient brands used. Dirt Pudding he!he!
100. g Al reacts with excess O2 to produce 150. g Al2O3 according to Calculate the theoretical and percentage yield. 4Al + 302 → 2 Al2O3. 79.4 % 14. Calculate the energy produced by the complete reaction of 150. g H2. 2H2 + O2 → 2H2O + 130KJ 4.83 x 103 kJ 15.
MA1210 Module 4 Systems of Equations and Matrices 10/13/14 Pamela 1. 2a + b = 700 a + 4b = 1400 -2a -8b = -2800 2a - 2a + b - 8b = 700 – 2800 Combining like terms gives us: -7b = -2100 Divide both sides by -7, which gives us: b = 300 We now know that 1 packet of brownies contain 300 calories. To find out the number of calories in 1 packet of apples, simply replace b with 300 in either of our original equations. I will use the first equation, 2a + b = 700: 2a + 300 = 700 -----> 2a = 700 - 300 -----> 2a = 400 Finally, divide both sides by 2, giving us: a = 200 Therefore each packet of apples contains 200 calories and each packet of brownies contains 300 calories. 2. a+b=150, 80a+60b=10000
Osmotic pressure is colligative properties (which are properties of solutions that depend upon the ratio of the number of solute particles to the number of solvent molecules in a solution (Chemistry). Osmosis is essential in biological systems. The aim for this lab report is to assess the effect of weight and length of 5 different concentrations of a salt solution on 6 different potato wedges over 24 hours. To do this we will research how the effect of different salt solution concentrations will have an affect on 6cm length potato wedges. Research Question: How will the different potato wedges submerged in various salt solutions affect on the weight and length of the potato wedges?
Strategy For this coursework, I will be investigating the following question: ‘How do different concentrations of salt solutions affect the mass of the potato after the process of osmosis?’ Osmosis is the movement of water particles from a high concentration of water particles to a low concentration across a partially permeable membrane. A partially permeable membrane is a membrane that acts as a barrier to some molecules but allows others to freely diffuse through. The partially permeable membrane of cell membranes prevent large molecules such as Sucrose, protein and starch to pass through but allow smaller molecules such as oxygen, carbon dioxide and water, glucose and amino acids to proceed. In this coursework we will be using potato to test the rate of osmosis. If the area around a cell has a higher water concentration it will gain water by osmosis.