Having two sets of chromosomes is known as (2n) _______diploid___________. ANSWER: 6. Eggs and sperm are _______haploid_________ (n). ANSWER: Next Give one characteristic of each of the following phases of Meiosis I. Prophase I: During prophase I, homologous chromosomes pair and form synapses, a step unique to meiosis Metaphase I: Bivalents, each composed of two chromosomes align at the metaphase plate Anaphase I: Each of the daughter cells is now haploid Telophase I: Nuclear envelopes may reform 7. Does the S phase (DNA replication) occur after Meiosis 1?
After meiosis the cells then undergo one round of mitotic division which gives rise to a total of eight haploid ascospores. Although S. fimicola is self fertile they can be crossed. It is the sexual phase where two haploid strains can fuse to form diploid zygotes (Mertens, 2001). These diploid zygotes are encased in the ascus. If two mycelia meet the two haploid nuclei can fuse to form a heterozygous diploid.
My control variable was the light microscope, the onion root tip and whitefish slides. Theory: By the end of this lab, I will have properly identified each phase of meiosis and mitosis in the onion root tip and whitefish slides based on my knowledge from in-class lectures, my diagrams and in-class notes. Mitosis occurs in whitefish and onion root tips, and it is easily observable. Before mitosis the cell is in interphase, this part of the cell cycle the cell will have a distinct nucleus and nucleoli where the threads of chromatin are duplicated. After duplication the cell is ready to begin mitosis and its starts with a step known as prophase.
These sister chromatids are then separated in anaphase as the spindle microtubules attaches to centromere and pulls the sister chromatids to opposite poles. As the sister chromatids separate they are called chromosomes. This means that each pole has the same chromosomes (same genetic material). Finally the microtubules break down, the chromosomes uncoil and the nuclear membrane reforms. The cell then divides into two daughter cells with genetically identical
Less germinated in the presence of 1% ammonium nitrate compared to the spores not in the presence of ammonium nitrate. In other studies done, when ammonium is used to provide the nitrogen source for photosynthetic spores, they will not grow or germinate properly, and may show abnormalities and inhibited growth (Melan & Whittier, 1990). That is exactly what our experimental data showed us. After preforming the tests and compiling all the replicate data, we found that in the control group there was an average of 50.5 germinated spores per plate. In the plates containing 1% ammonium nitrate there was an average germination rate of 28.5 spores per plate.
2. How has DNA sequencing affected the science of classifying organisms? Experiment 1: Dichotomous Key Practice Data Tables and Post-Lab Assessment Table 3: Dichotomous Key Results Organism | Binomial Name | i | | ii | | iii | | iv | | v | | vi | | vii | | viii | | ix | | xi | | xii | | xiii | | Post-Lab Questions 1. What do you notice about the options of each step as they go from number one up? 2.
In this experiment the mitochondria will be studied using in vitro methods. The Mitochondria will be extracted using a Centrifuge and Rapid Homogenization from an etiolated Mung bean seedling. The interaction of the mitochondria to different chemical conditions will be studied to determine how the Kerb cycle and oxidative phosphorylation function. The chemical condition will include the effects of the presence and absence of Na azide, Na succinate and malonate on the mitochondria. This will be tested using a 2, 6 dichlorophenolindophenol (DCPIP) dye which is coloured in its oxidized form but when it is reduced it will become colourless.
Cell Structure & Function Written By Bonnie Keegan Date 3rd October 2014 This assignment will describe the function and structure of a Liver cell (hepatocytes), explain why cells undergo cell division during growth and repair of liver tissue and describe the differences between a mature hepatocyte and a human stem cell. A cell is the smallest unit that is capable of performing life functions. Eukaryotic cells are found in animals, plants, fungal and protoctista organisms. They have membrane-bound organelles and a true nucleus. Animal cells have a cell membrane allowing them flexibility to change structure into all types of organs and then turn into systems in plant cells they are slightly different as they have a cell wall giving it a more solid structure.
Write a caption for each drawing that indicates the features that placed the cell in its stage. 3. Complete the lab worksheet data table and analysis to determine quantitative estimates of stage duration. Survey at least 100 cells, noting the number in each stage of the cell cycle. Make sure you count cells from a representative area of rapid cell
After placing each in a respective solution, and ~24 hours later, the same process of mass and volume finding was repeated. With the new calculations, the osmolarity of the potato could be found. Hypothesis: The hypothesis states that the potato cores’ osmolarity ranges in the 0.2M – 0.4M zone. That, in turn, means that all solutions less than the aforementioned osmolarity are hypotonic while the solutions greater are hypertonic. Materials: * Cork Borer * Ruler * Graduated Cylinder * 6 test tubes * Aluminum Foil * 6 different sucrose molarities (0.0M, 0.2M, 0.4M, 0.6M, 0.8M, 1M) * Laboratory balance Procedure: 1.