A) How many mosm solute will 1 gram of NaCl yield? Show your calculations. (1gNaCl/1)*(1000mg/1gNaCl)(2/58mg)=34.5mOsm. 3. Mixed Solutions: If 1 mmole of glucose (180mg=1mOsm) and 1 mmole of NaCl (58mg=2mmOsm) are put into a beaker and distilled water added to make 1 liter, the osmolarity is 3 mOSm/L.
If the reaction is first order, its graphical representation is seen as ln[A] (natural log of concentration) vs. time, and the slope of its like is also the negative rate constant. Finally, for a second order reaction the graph is shown as 1/[A] (inverse of concentration) vs. time, and the slope of its given line is the positive rate constant. By understanding the rate law and finding the value of the correct rate constant with respect to the order of the reaction, one can determine the half-life of the crystal violet. This is because the crystal violet undergoes a decay reaction with the sodium hydroxide. According to Beer's Law, the absorbance of crystal violet is proportional to its concentration.
Problem: What is the effect of pH on beef liver catalase activity when it is measured by the change in temperature? The pH will be measured using a pH probe; and the temperatures will be measured using four temperature probes. Hypothesis: It is hypothesized that if the pH of the beef liver catalase solution is adjusted from its initial pH with the use of an acid or base, then a temperature difference will occur within the beef liver catalase solution. This is predicted because pervious experiments have shown that an increase in temperature may also lead to an increase in the number of ions in solution due to the dissociation of molecules. Since pH is a measure of the hydrogen ion
Use a calorimeter to measure the temperature change in each of three reactions. Calculate the heat of reaction, ∆H, for the three reactions. Use the results to confirm Hess’s law. Ev al Figure 1 ua tio Na+(aq) + OH–(aq) + H+(aq) ) + Cl–(aq) → H2O(l) + Na+(aq) + Cl–(aq) ∆H3 = ? n (3) Solutions of aqueous sodium hydroxide and hydrochloric acid react to form water and aqueous sodium chloride.
The result proved: Contract to the hypothesis, at pH 12, activity of enzyme Catecholase and the rate of reaction decreased. Introduction pH is a measure of the concentration of hydrogen H+ in solution so the higher concentration hydrogen ion, the lower pH. pH is one of the most important factors affect to human body. pH was divided three parts on pH scale from pH 0 to pH 14: at pH 7, solutions are neutral. pH > 7 is alkalinity environment that will bind hydrogen ion, and pH < 7 is acidic environment that will donate hydrogen ion.
In this experiment, the amount of energy (heat) involved in a chemical change will be determined. When alcohol burns it produces carbon dioxide and water as products. Energy is also released in the reaction. The alcohols that will be used are, methanol CH3OH, ethanol CH3CH2OH, propanol CH3(CH)2OH, butanol C4H9OH, octanol C8H18O, and paraffin wax C25H52. The heat obtained when a known mass of alcohol or paraffin wax burns will be used to warm a measured volume of water.
State the optimum pH for sucrase activity and describe how sucrase activity changes at more acidic and more alkaline pH values. See Table 2: Effect of Temperature on Sucrase Activity See Graph, Effect of Temperature on Sucrase Activity 2. Was the rate of increase of sucrase activity higher at a pH of 8.5 or a pH of 5.5? 3. State the optimum temperature for sucrase activity and describe how sucrase activity changes at lower and higher temperatures.
The resulting product was [Co(NH3)5Cl]Cl2 and yield was 4.453g (.017 mol, 84.8%) Distilled water (25mL) was added to concentrated ammonia (5mL) in a 125mL Erlenmeyer flask. The reaction was heated and stirred, then [Co(NH3)5Cl]Cl2 (.0060 mol) was added to the solution. The reaction mixture was vacuum filtered, and the filtrate was cooled in an ice bath. 6M HCl was then added until the solution was neutral to litmus. NaNO2 (.0217 mol) was added to the solution and was allowed to react for five minutes.
Volume of gas = molar volume x number of moles The molecular formula of gaseous hydrocarbons (CxHy) and organic compounds (CxHyOz) can be determined by combustion in excess oxygen to form carbon dioxide and water, using the following equations: CxHy + (x+ y/4) O2 x CO2 + y/2 H2O CxHyOz + (x+ y/4- z/2) O2 x CO2 + y/2 H2O Example 4 When 10 cm3 of a gaseous hydrocarbon was combusted in excess oxygen in an enclosed vessel, the volume of gas (measured at 298K) was reduced by 25 cm3. The addition of excess NaOH (aq) caused a further reduction in gas volume of 40 cm3 (measured at 298 K). The pressure in the vessel was maintained constant at 1 atm throughout the measurements. Find the molecular formula of the
5. Potassium hydroxide solution: Use 0.01 M potassium hydroxide, 0.56 g/L. 6. Ammonium hydroxide solution: Add water to 10 mL of concentrated ammonium hydroxide solution to make 82 mL of a stock solution. Use 10 mL of the stock and dilute to 1 L with distilled water.