Acid Base Titration

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Chemistry lab report 28th of Sep 2009/ Monday Aya Naji Shnawa Experiment 1.3 An acid base titration *data collection and processing *conclusion and evaluation DATA COLLECTION AND PROCESSING: Readings 1st trail 2nd trail 3rd trail 4th trail Average Initial ±0.05cm 3 0.0 0.0 0.0 0.0 0.0 Final ±0.05cm 3 20.5 21.5 21.0 21.1 21.0 Table 1.1: a presentation of processed data in all the trails. ________________________________________ The experiments The difference 1st to 2nd 1.0 2nd to 3rd 0.5 3rd to 4th 0.1 Table1.2: the difference of the final readings between the experiments ________________________________________ The average Standard deviation 21.0 0.4 Table1.3: the difference between average and standard deviation. ________________________________________ The sum of the difference The average 1.6 0.5 Table 1.4 the average of the difference. PRESENTATIONN OF DATA: Chart 1.1: the final readings of each of the four trails. ________________________________________ Chart 1.2: the difference between the readings in each of the trails. Chart 1.3: the difference between the sum and the average. CONCLUSION AND EVALUATION CONCLUSION: Equivalence point is the point at which the moles of H+ is equal to the moles of OH+,an indicator is used to show the equivalence point during a titration. in a titration the method is about totaling one reactant from the burette (regularly the acid),to a known volume of the other reactant in a conical flask(regularly the base) . In order to find the concentration of NaOH we need to tag along the following steps: a- note down the balanced chemical equation for the reaction C8H5O5K+NaOH→C8H4O4KNa+H2O b- pull out applicable information from the experiment: C8H5O5K V=0.025 dm3 C=0.2M NaOH V=0.021 dm3 C= ?? c- calculate number of moles

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