2NaCl + H2SO4 —> Na2SO4 + 2HCl 4. If 0.380 mole of barium nitrate is allowed to react with an excess of phosphoric acid, how many moles of barium phosphate could be formed? 3Ba(NO3)2 + 2H3PO4 —> Ba3(PO4)2 + 6HNO3 5. Calculate the number of grams of carbon dioxide produced from the burning of 1.65 moles of C3H8. C3H8 + 5O2 —> 3CO2 + 4H2O 6.
4 Calculate the molar mass of these compounds: (relative atomic masses: H = 1; N = 14; O = 16; S = 32; Cu = 64; Br = 80; Pb = 207) (a) copper nitrate, Ca(NO3)2 (b) lead bromate, Pb(BrO3)2 (c) ammonium sulfate, (NH4)2SO4 5 The equation for the complete combustion of methane is shown below. CH4 + 2O2 → CO2 + 2H2O When 80 g of methane is completely combusted, 220 g of carbon dioxide and 180 g of water are formed. (a) Why is the mass of carbon dioxide formed greater than the mass of methane burnt? (b) Calculate the mass of oxygen that reacted. (c) Calculate the mass of water formed when 20 g of methane undergoes complete combustion.
Seventy five percent of the table is made up of metals, and a couple of the columns on the right of the table have gases. There are only two elements that are liquids- mercury and bromine. Column 1 contains the alkali metals, which suddenly combust when exposed to air or water. Columns 3-12 are the transition metals, which contain heavier atoms, which are more flexible in how they organize their electrons. Column 17 is made up of the more reactive gases- the halogens.
RESULTS The first flask held .305 grams; the second, .454 grams; and the third, .477 grams of unknown gas. According to the ideal gas law, at a pressure of 762.0 mmHg and 16.0ÂºC, a vessel of 250 ml will contain .0105 moles of gas, while a vessel of 252 ml will contain .0106 moles of gas. Dividing the number of grams of unknown gas contained in each flask by the corresponding number of moles contained in that vessel resulted in a molar mass for each of the flasks. The
As a result of the gas shield, a clean weld is formed. This prevents oxidization from occurring. MIG.TIG-Both are argon welding as both the processes uses argon for shielding as it is a innert gas. (Inert gas - Used to shield the electric arc from outside contaminants and gases which may react with the weld. An inert chemical is one with a full outer shell of electrons which do not normally react with other substances.
Therefore, acetic acid was used for this experiment. It reacted with the sodium hypochlorite to give hypochlorous acid, which thenreacted with the oxygen of the alcohol. Steam distillation was used to isolated product, and then was extracted into the distillate with ether with the addition of dying agent calcium chloride. Finally, the ether was removed to get the product, cyclohexanone with the "salting out" process. The process of salting out was used to separate cyclohexanone from the aqueous solution to purify the product.
The powder that remains will have lost some mass as smoke, but this resultant mass is still more than the mass of the metal that was burnt. Burning magnesium in air is a chemical reaction called oxidation and the compound produced is totally different from the two elements that have been combined. Each element is made up of atoms and the compound is made up of two elements joined together. The chemical formula for the reaction is below; 2Mg + O2 --> 2MgO Magnesium + Oxygen -> Magnesium Oxide The equation above shows that magnesium and oxygen have combined as the product of the reaction, their mass of each element has also combined in the reaction. Magnesium is a very reactive metal which when heated burns with a white flame.
Low melt rates are employed for large solidification range (liquidus-to-solidue) alloys to avoid seggregation. Melt rates are scaled to diameter. Copper plates thicker than 2-3 mm are very difficult to braze or weld due to very high thermal conductivity. When you weld one part, previously welded part will melt and open up. Steel conductivity is
Bromination: Aniline reacts with bromine water at room temperature to give a white precipitate of 2,4,6 tribromoaniline. Nitration: Direct nitration of aniline yields tarry oxidation products in addition to the nitro derivatives. Moreover, in the strongly acidic medium, aniline is protonated to form the anilinium ion which is meta directing. That is why besides the ortho and para derivatives, significant amount of meta derivative is also formed. However, by protecting the –NH2 group by acetylation reaction with acetic anhydride, the nitration reaction can be controlled and the p-nitro derivative can be obtained as the major product.