= (x-bar-E,x-bar+E) = (3.3048-0.0818,3.3048+0.0818) (b) What sample size would be necessary to estimate the true weight with an error of ± 0.03 grams with 90 percent confidence? n=[z'*s/E]^2 n=[1.645*0.131989/0.03]^2 = 52.38; rounding up, n=53 (c) Discuss the factors which might cause variation in the weight of Tootsie Rolls during manufacture. (Data are from a project by MBA student Henry Scussel.) There are many factors that can influence weight variation in the production of Tootsie Rolls. The equipment that the Tootsie Rolls are manufactured on could be a factor if they are not calibrated properly or as required.
20. mol H2 reacts with 8.0 mol O2 to produce H2O. Determine the number of grams reactant in excess and number of grams H2O produced. Identify the limiting reactant. 8.1 g H2 , 2.9 x 102 g H2O 17. How many litres of O2 gas are required to produce 100. g Al2O3?
So, 2000 = 30000/Square root of sample size. Solving for the Square root of sample size, we get Square root of sample size = 30000/2000 = 15. Taking its square, the sample size is found as 225. Chapter 9 Exercise 1 No it is not a good defense. If you choose 40 random employees from the corporation, the standard error would equal 6/Square root of 40 = .95 days.
Less germinated in the presence of 1% ammonium nitrate compared to the spores not in the presence of ammonium nitrate. In other studies done, when ammonium is used to provide the nitrogen source for photosynthetic spores, they will not grow or germinate properly, and may show abnormalities and inhibited growth (Melan & Whittier, 1990). That is exactly what our experimental data showed us. After preforming the tests and compiling all the replicate data, we found that in the control group there was an average of 50.5 germinated spores per plate. In the plates containing 1% ammonium nitrate there was an average germination rate of 28.5 spores per plate.
It was discovered that the mean life was 362 days and the sample standard deviation was 10 days. The research department decided to conduct the test at the 0.05 level of significance whether the modification actually increased the life of the AAA battery. What was their decision rule? A. Reject the null hypothesis if computed z is 1.96 or greater.
Test Tube 4 1.5mL/1 x 1L/1000mL x .5/1L = 7.5 x10-4 Test Tube 5 2.0mL/1 x 1L/1000mL x .5/1L = 1.0 x10-3 Determine LR Test Tube One (.001mol NaI / 1.5 x 10-4mol Pb(NO3)2) = 6.66 (1 / 1) = 1 6.66 > 1 Pb(NO3)2 is the Limiting Reactant Test Tube Two (.001mol NaI / 2.5 x 10-4mol Pb(NO3)2) = 4 (2 / 1) = 2 4 > 2 Pb(NO3)2 is the Limiting Reactant Test Tube Three (.001mol NaI / 5 x 10-4mol Pb(NO3)2) = 2 (2 / 1) = 2 2 = 2 Test Tube number Three is the Exact stoich ratio Test Tube Four (.001mol NaI / 7.5 x 10-4mol Pb(NO3)2) = 2 (2 / 1) =
Round the number of years to the nearest hundredth. 67) A certain radioactive isotope has a half-life of approximately 1400 years. How many years to the nearest year would be required for a given amount of this isotope to decay to35% of that amount? 68) An artifact is discovered at a certain site. If it has 74% of the carbon-14 it originally contained, what is the approximate age of the artifact to the nearest year?
Week Three Discussion Questions • Can the probability be more than 1 or less than 0? Explain why or why not. According to the Statistics for Business and Economics book, probabilities have to follow two basic rules and one of them is that the number has to be between 0 and 1. Therefore, the probability cannot be more than 1 and less than 0. • Based on the data collected on a typical day, what is the probability that oil change will take 15 minutes or less time?
Name: Patrick Morefield Date: December 06, 2006 Lab Partner: Gabriel Rodriguez Unknown No. : 941 Report Sheet Colligative Properties: Freezing-Point Depression and Molar Mass |1. |Volume of cyclohexane |10..1mL | |2. |Mass of empty insulated test tube and spin bar |345.47g | | |Mass of stir bar, tube and cyclohexane |353.10g | | |Mass of cyclohexane |7.63g | |3. |Mass of insulated test tube, spin bar, cyclohexane and |353.25g | | |unknown | | |4.
Procedure: Refer to Chemistry Lab Manual pp. 33-35, 37. Results: The density of the yeast-sugar solution on day 1 was 1.05g/mL. On day 2, the density of the solution had dropped down to 1.00g/mL. We found the mass of our pure alcohol to be 10.23g.