889 Words4 Pages

Calculations involving Solutions (1)
Answer the following questions on file paper. Remember to set out your working neatly and clearly, showing all necessary steps. Give answers to the appropriate number of significant figures. Use Ar values when required as given on your copy of the Periodic Table.
1) Calculate the number of moles in each of the following solutions:-
a) 2.0 dm3 of 0.050 mol.dm-3 hydrochloric acid
b) 50 dm3 of 5 mol.dm-3 sulfuric acid
c) 10 cm3 of 0.25 mol.dm-3 potassium hydroxide [3]
2) Calculate the volume in cm3 of each solution that contains the following numbers of moles:-
a) 0.00500 moles of NaOH with concentration 0.100 mol.dm-3
b) 1.00×10-5 moles of HCl with concentration 0.0100 mol.dm-3
c) 9.25×10-3 moles of KCl with concentration 0.250 mol.dm-3 [3]
3) Find the concentrations of the following solutions in both mol.dm-3 and g.dm-3:-
a) 0.400 moles of HCl in 2.00 dm3 of solution
b) 12.5 moles of H2SO4 in 5.00 dm3 of solution
c) 1.05g of NaOH in 500 cm3 of solution [6]
4) In a titration, 25.0 cm3 of a solution of sodium hydroxide required 18.80 cm3 of hydrochloric acid of concentration 0.0500 mol.dm-3 for neutralisation. Find the concentration of the sodium hydroxide in both mol.dm-3 and g.dm-3. [3]
NaOH + HCl ( NaCl + H2O
5) Calculate the volume of 0.05 mol.dm-3 potassium hydroxide solution that is required to react exactly with 25.0 cm3 of 0.0150 mol.dm-3 nitric acid. [2]
HNO3 + KOH ( KNO3 + H2O
6) In a titration, 20.0 cm3 of barium hydroxide solution required 28.60 cm3 of sulfuric acid of concentration 0.0250 mol.dm-3 for neutralisation. Find the concentration of the barium hydroxide in both mol.dm-3 and g.dm-3. [3]
Ba(OH)2 + H2SO4 ( BaSO4 + 2H2O
7) In a titration, 25.0 cm3 of

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