Measure and record the diameter of each of the disks in meters. 2. Mathematically record the radius of each of the disks as well. 3. To measure the circumference of the disk, make a mark on the disk and place the disk on the meter stick with the mark coinciding with a meter stick reading.
They are interchangeable because 1g=1mL. 5. A solid block with a length of 6.0 cm, a width of 3.0 cm, and a height of 3.0 cm has a mass of 146 g. What is the block’s density? Show all work. V=lxwxh v=6.0cmx3.0cmx3.0cm= 54cm D=m/v d= 146g/54cm= 2.7g/cm3 6.
7-7 Geometric Sequences as Exponential Functions Determine whether each sequence is arithmetic, geometric, or neither. Explain. 1. 200, 40, 8, … SOLUTION: Since the ratios are constant, the sequence is geometric. The common ratio is 2.
Show the steps of conversion that you used. Adding leading zeroes creates the number 001101102 which can be split into 00112 and 01102 the hexadecimal value for these two bytes are 316 and 616 respectively so this number would be 3616 Exercise 1.3.6 Represent the hexadecimal value f616 in binary and decimal. Show the steps of conversion that you used. F16 = 11112 and 616 = 01102 when put together the binary value is 111101102 which is equal to 246. Lab 1.3 review 1.
Chapter 1 review questions 1. Which of the following is true about 1 bit? a. Can represent decimal values 0 through 9 b. Can be used to represent one character in the lowercase English alphabet c. Represents one binary digit d. Represents four binary digits 2.
Using the same electronic balance, the average mass of five copper slugs, in grams, will be determined. Lastly, by using the electronic balance again, the weight of two different unknown weights, in grams, will be determined by the weighing by difference method. Using both the direct weight and weighing by difference techniques, the weight of the copper slug (2.98 g) and the two unknown weights can be fairly accurately determined using the centigram balance. However, since the electronic balance can determine mass out to three decimal places, the electronic balance was more accurate weighing the copper slug (3.022 g) than the centigram balance using the direct weight and weighing by difference methods. Determining the mass of the two unknown weights (unknown weight #1 and #2) was determined using only the centigram balance using the weighing by difference method.
The R-squared value shows us the correlation between the two variables in each graph that we were comparing. A consistent, precise R-squared value would be ideally 1. In all three cases, only one of our methods gave us this result: Titration. So given our results titration was the most precise method. But, our Ideal Gas Law method was more precise than crystallization from the previous week due to our newly found R-squared value of 0.8909.
There are two types of special right triangles: 45-45-90 and 30-60-90. The legs on a 45-45-90 triangle are 1 and 1 and the hypotenuse is the square root of 2. The legs on a 30-60-90 triangle are 1 and the square root of 3 and the hypotenuse is 2. If you were to take the three trigonometric functions of either 45 degree angle, you would get the (square root of 2)/2 for both cosine (x) and sine (y) and 1 for tangent (y/x). If you were to take the three trigonometric functions of the 30 degree angle, you would get the (square root of 3)/2 for cosine, ½ for sine and the (square root of 3)/3 for tangent.
Exercise 1.3.1 What is the decimal value of Byte 1 by itself? What is the decimal value of Byte 2 by itself? -6400 -233 Exercise 1.3.2 What is the decimal equivalent of the binary sequence in Figure 1- 12 (the combined sequence of Byte 1 and Byte 2 as a single decimal value)? How does this compare to the individual values of Byte 1 and Byte 2? -6633 -There is an increase of bits.
2.12 b. 1.734 c. -1.740 d. 1.740 ANSWER: d -same process but now go to one tailed α=0.05 and dof = 17 4. Read the t statistic from the table of t distributions and circle the correct answer. A one-tailed test (lower tail), a sample size of 10 at a .10 level of significance; t = a. 1.383 b.