This explanation can be demonstrated in table 3 also because the results of the reactions demonstrates that chloride reacted more by the color of the product compared to the color of chloride in the mineral oil. Also it also demonstrates that iodine is the weakest oxidizing agent because the results show that iodide didn’t change much from the color that it showed in the mineral oil. In example 6 we have shown the activity series for the halogens used in this
Focus Question Should chemists prepare Zinc Iodide, from its elements or from a Double Replacement Reaction between Barium Iodide and Zinc Sulfate? -To put things into perspective in terms of cost efficiency, zinc granules cost about $62.50 per kilogram or $.0625 per gram. Also, Iodine chips cost about $.1498, Barium Iodide Dihydrate costs about $.886 per gram, and Zinc Sulfate Heptahydrate costs about $.0405 per gram. According the chemical reaction listed below, the double replacement reaction creates a solid Barium Sulfate precipitate This means that the ZnI2 is less pure than it would be from just the Zinc and the Iodine. With the elemental reaction you get ZnI2 as your only product thus indicated that it is “pure” Zinc Iodide.
Akella Turnbull Date: February 2, 2015 Lab Partner: Shubh Rana South Street Seaweed Seaport Lab Summary: In this lab, we were able to make our own tinctures of iodine by extracting iodine from a Japanese seaweed, referred to as Fucus seaweed. We were able to conduct a hot water extraction from this seaweed in order to isolate the iodide, which is a solution that can be used to manufacture a pharmaceutical product. In order to prepare a tincture of iodine for testing we had to use a balance, ignite a Bunsen burner, and heat and filter a solution. In doing so, we had to prepare 6 grams of dry seaweed by cutting it into ½ inch pieces and placing it into a beaker filled with ¾ distilled water. Then after agitating the seaweed to remove monosodium glutamate and pouring off the water, 40 mL of distilled water was added to the seaweed and heated.
Appearance Iodine: silver sphere solid Zinc Shot: Round flat silver Zinc Granular: pencil shaving like silver solid Potassium iodide: white thick powder Focus Question: How well does the appearance and solubility of iodine and zinc respectively compare with information presented in the CRC Handbook of Chemistry and Physics? The appearance and solubility of iodine and zinc that we observed n the lab are very similar to the information presented in the CRC handbook of chemistry and physics. The iodine pieces we observed in lab were insoluble in water, and soluble in potassium iodide (very soluble), mineral oil (slightly soluble), and alcohol (slightly soluble). This consigns with what the CSC handbook stated that’s potassium iodide,
Using the same electronic balance, the average mass of five copper slugs, in grams, will be determined. Lastly, by using the electronic balance again, the weight of two different unknown weights, in grams, will be determined by the weighing by difference method. Using both the direct weight and weighing by difference techniques, the weight of the copper slug (2.98 g) and the two unknown weights can be fairly accurately determined using the centigram balance. However, since the electronic balance can determine mass out to three decimal places, the electronic balance was more accurate weighing the copper slug (3.022 g) than the centigram balance using the direct weight and weighing by difference methods. Determining the mass of the two unknown weights (unknown weight #1 and #2) was determined using only the centigram balance using the weighing by difference method.
Introduction In Chemistry 1211 lab the main objective was to identify the name of the unknown acid #2651145-PLF13 that was issued by the instructor. Melting point, titration of the unknown acid, calculation of equivalent weight, pKa, solubility tests, and properties of a hydrochloric acid; these procedures were used to characterize the unknown acid and then compared with known substances using GSU Chemistry department search engine. By doing this experiment he or she will develop an understanding of the properties of organic acids and differences between properties of a strong acid such hydrochloric acid. Experimental The first procedure to identify the unknown organic acid was finding the correct melting point. This was done by taking small amounts of the unknown acid.
Part B: The graduated pipet’s average density at 22.3 °C was determined to be 0.9785g/mL with a percentage error of 1.89% shows the graduated pipet to be more accurate and precise. Part C: Density of an unknown NaCl solution was measured and a calibration curve used to determine the percentage of NaCl by mass in the solution. y=0.007x + 0.998 which concluded that the concentration of the sodium chloride solution was 3.14%. INTRODUCTION Anything that you can see, touch, taste or smell, occupies space and has mass, it is called matter. Matter can be a gas, a liquid,
8) See column 8 and back for work. 9) My accuracy was not really bad but it wasn’t that good, some of the guesses I made were almost accurate but others were way off. Atom | Average mass of one atom | Mass relative to carbon (#:1) | Atomic mass (from periodic table) (g) | Number of atoms in a relative mass (column 4/ column 2) | Carbon | 2.00E-23 | 1 | 12.01 (g) | 6.005 x 1023 | Iron | 9.30E-23 | 4.65:1 | 55.85 (g) | -65.15 | Aluminum | 4.49E-23 | 2.245 | 26.98 (g) | 6.010 x 1023 | Zinc | 1.08E-22 | 5.4 | 55.85 (g) | 5.17 x 1023 | Lead | 3.44E-22 | 17.2 | 207.2 (g) | 6.024 x 1023 | Copper | 1.05E-22 | 5.25 | 63.55 (g) | 6.052 x 1023 | PART:2 Question 1) I think carbon’s role is something to do with global warming I think I’m not sure, this doesn’t make sense because why does global warming have anything to do with the mole or even chemistry. | 2) In column 5 all the numbers are very close to Avogadro’s number 6.02 x 1023. 3) One gram = 6.02 x 1023 amu.
I think Archimedes’ Principle if done properly can be done more accurately because liquid displaces evenly. You are given a small piece of gold colored material and want to determine if it is actually gold. Using the Archimedes Principle you find that the volume is 0.40 cm3 and the mass is 6.0 g. What conclusions can you reach from your simple density analysis? It isn't gold because gold has a higher density. Exercise 3: Concentration, Solution, and
The purpose of this lab was to find out what Group 1 metal is in the unknown carbonate. The unknown carbonate was reacted with CaCl2. Using the mass of the precipitate formed in the reaction the molar mass of the unknown carbonate was found, revealing its true identity. After doing the calculations I got a molar mass 0.8685 g (unknown) / mol. Then, I compared my molar mass to the molar masses in the group 1 metals on the A.P.