A2a. Experimental Design: By using commonly available materials and accurate measuring tools the experiment will allow others to obtain similar results. Connect the multimeter to the two ends of the coil of wire and vary the temperature of the coil of wire. Materials: Precision multimeter to measure resistance Digital timer to measure time periods Multimeter test clips 1000 foot coil of wire (28 gauge) High-precision digital thermometer 1 liter plastic vessel Tap water: Room temperature Ice/Water mix
(8 marks) Find the energy dissipated in the resistor. Hints: The difference between the initial total and final total energy stored in the capacitors. (10 marks) Answers (a) Final potential V = Q/5C for both capacitor (b) The charge on the smaller cap = Q/5 The charge on the bigger cap = 4Q/5 (c) Final energy in the smaller cap is Final energy in the bigger cap is (d) Initial total energy stored is Final total energy stored is The energy dissipated in the resistor (10 marks) (10 marks) (4 marks) (3 marks) (4 marks) (4 marks) Question 3 (28.39) In the circuit of the figure below, the switch S has been open for a long time. It is then suddenly closed. Take = 100.0 V, R1 = 10.0 kΩ, R2 = 100 kΩ, and C = 10.0 µF.
Name: Robert Christopher Date: 16/2/2011 ID: 0670000687 COMPARISON OF ARTERY AND VEIN Raw Data Table 1: Below are the results of the experiment completed through cutting down the vein and artery into a ring-like shape. A 10g-50g of mass is used to suspend the artery and vein; and measured it with a 1-meter ruler standing 90˚ on the table to distinguish how long it stretches with a specific mass weight. Average Length ± 0.05g/mm | Mass ± 0.05mm/g | Artery | Vein | | Trail 1 | Trial 2 | Average | Trial 1 | Trial 2 | Average | 0g | 393 | 377 | 385 | 370 | 374 | 372 | 10g | 392 | 376 | 384 | 368 | 372 | 370 | 20g | 391 | 375 | 383 | 366 | 370 | 368 | 30g | 390 | 374 | 382 | 364 | 368 | 366 | 40g | 389 | 373 | 381 | 362 | 366 | 364 | 50g | 388 | 372 | 38 | 360 | 364 | 362 | Data Presentation Table 2: Below are the results of the artery and vein’s length difference in mm. These results were known when the average results from the two trials were calculated. The results can be calculated with the following formula: "trial 1 + trial 2; then divide the result by 2 to get the average mean results”.
Experiment 2.1 Absorption Spectrum of a Conjugated Dye Table of contents * Page 1 Title sheet & Table of contents * Page 2 Introduction & Abstract * Page 3 Abstract continued, Method & Results * Page 4 Results * Page 5 Results * Page 6 Results * Page 7 Discussion * Page 8 Introduction: The purpose of this experiment was to determine a relationship between energy levels and wavelengths in a range of dyes in a manner that would satisfy the Schrodinger wave equation and Eigen functions. This would be achieved by finding the maximum absorption for a particular dye and using that information, working out an alpha value to determine the wavelength of the molecule and from that, the discrete energy value. A successful experiment would involve the wavelength increasing as the number of conjugate electrons increases and also show a decrease in energy of the wavelength. Abstract: UV Vis spectroscopy is a method of analysis that measures transitions between a ground state and an excited state in a molecule. This method of analysis was used to determine the maximum absorption for the four dyes used in the experiment.
Different masses 4. Timer Methods: Newton’s law predicts that acceleration should be proportional to the difference of the masses and proportional to their sum. A=(m1-m2)/(m1+m2)*g. The g= 9.8 m/s^2 is the acceleration due to the gravity. So, we ser the single pulley on the table, and cut a 90 cm string and hanging over the pulley. And mass were stacked on the each hanger of the both sides.
The battery’s positive lead pushes current away from that lead, and c. The circuit creates a direct current. 2. A PC NIC and a switch port create one electrical circuit to use when sending data. The sender creates a (maximum) 1-volt electrical signal with a frequency of 1000 hertz. Which of the following facts are also true?
Student designed practical investigation Title: Atwood’s Machine (Newtons 2nd law of motion). Partner: Qurban Aim: To explore how two different masses act with each other on a pulley and therefore calculate acceleration a (theoretical and experimental) and the Tension T. Hypothesis: When both masses are the same, there should be no acceleration. The larger the ratio between one mass and the other, the higher the acceleration should be. Materials: Pulley, string, mass 1 + 2, ruler, stopwatch, scissors Apparatus: Theory: Since we are trying to find a, the equations we need are: For experimental a: Transposed to: Theoretical a: For tension: where x = displacement u = initial velocity t = time taken = mass 1 = mass 2 Let Method: 1. Set up the apparatus in the diagram above.
Below is a table showing the elements that make up the wall. Elements | Thickness (m) | Thermal Conductivity (W/mk) | Resistance (m²k/w) | Rsi | - | - | 0.123 | Plaster | 0.012 | 0.16 | 0.075 | Block | 0.100 | 0.19 | 0.526 | Insulation | 0.150 | 0.035 | 4.286 | Brick | 0.100 | 0.84 | 0.119 | Rso | - | - | 0.055 | TOTAL | | | 5.184 | Resistance is calculated through (Thickness divided by Thermal Conductivity) Once we have the total resistance (rate of heat released) we can work out the U-value using the following formula: 1 U-value = Rt 1 = 5.184 = 0.19 w/m²k Now that I have calculated the U-value, I can calculate the amount of heat loss through the following: = Area x U-value x Temperature Difference = 150 x 0.19 x 14 = 399w Therefore as shown above the total amount of heat loss through 150m² of cavity wall is 399w. 2. Sound Calculation If the intensity of a sound is measured at 0.04w/m², calculate the resultant decibel level (dB)! I dB = 10 log ( I ) where I = 1 x 10¹² 0.04 dB = 10 log ( 1x10¹² ) dB = 10 log ( 4x10¹º ) dB = 106 3.
1. INTRODUCTION Sir Isaac Newton produced three laws of motion. Newton’s second law of motion states that, “the acceleration (a) of an object is directly proportional to the net force acting on it and inversely proportional to its mass” (VUILLE, 86). This second law can be written into mathematical terms and written as: a = Fnet /m However, the equation above is more commonly seen as: Fnet = ma In these equations a represents the acceleration of the object, m is the objects mass Fnet represents the vector sum of all the forces acting on the object. The Atwood machine is an apparatus that explores the idea states above.