Answer: Here given, Im = 2.53 mA Dividing Amplitude of voltage Im by √2, 2.53 √2 = 1.8 Comment: Both values were not matching. There have more than 10% discrepancy. Q. 3. Calculate the impedance by the measured values of voltage and current from the oscilloscope.
6. Repeat step 5 four times. Data/Observations: Conclusion: Recall: We did a lab to learn about how the mass of an egg changes when it is put in different substances. Explain: We recorded the masses of two eggs every 15 minutes. One was put in water while the other was put in corn syrup.
23(5329)703<W< 25(5329)703 After I multiply I end up with 122567703<W< 133225703 Then I simply divide and end up with 174 < W < 189.5. So people who are 73 inches tall that way between 174 and 189.5 are probably not overweight. Now for the third equation I will use 25 and 30 in place of 23 and 25 in the above equation. 25(5329)703<W< 30(5329)703 Then I will multiply the parentheses. 133225703<W< 159870703 Then I must do the division.
A student calculated the theoretical yield of barium sulfate in a double replacement reaction experiment to be 1.35 g. When she filtered, dried and weighted her solid (precipitate), however, her yield was only 1.29 g. Calculate the student’s percent yield. 3. Before going to lab, a student reads in his lab manual that the percent yield for a difficult reaction to be studied was likely to be only 40% of the theoretical yield. The student’s pre-lab stoichiometric calculations predict that the theoretical yield should be 12.5 grams. What is the student’s actual yield likely to be?
8) See column 8 and back for work. 9) My accuracy was not really bad but it wasn’t that good, some of the guesses I made were almost accurate but others were way off. Atom | Average mass of one atom | Mass relative to carbon (#:1) | Atomic mass (from periodic table) (g) | Number of atoms in a relative mass (column 4/ column 2) | Carbon | 2.00E-23 | 1 | 12.01 (g) | 6.005 x 1023 | Iron | 9.30E-23 | 4.65:1 | 55.85 (g) | -65.15 | Aluminum | 4.49E-23 | 2.245 | 26.98 (g) | 6.010 x 1023 | Zinc | 1.08E-22 | 5.4 | 55.85 (g) | 5.17 x 1023 | Lead | 3.44E-22 | 17.2 | 207.2 (g) | 6.024 x 1023 | Copper | 1.05E-22 | 5.25 | 63.55 (g) | 6.052 x 1023 | PART:2 Question 1) I think carbon’s role is something to do with global warming I think I’m not sure, this doesn’t make sense because why does global warming have anything to do with the mole or even chemistry. | 2) In column 5 all the numbers are very close to Avogadro’s number 6.02 x 1023. 3) One gram = 6.02 x 1023 amu.
Repeat steps 1-5 for trial 2. Variables and Control test: Independent Variable: Amount of each reactant poured into the test tubes Dependent Variable: Height of each solution Constant variables: Amount of time waiting for solution Data Table: Test tube # | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | Trial 1 | 0.5 cm | 1.0 cm | 1.1 cm | 1.5 cm | 1.5 cm | 1.5 cm | 1.3 cm | 1.5 cm | Trial 2 | 0.5 cm | 0.7 cm | 1.0 cm | 1.0 cm | 1.3 cm | 1.7 cm | 1.9 cm | 1.5 cm | Observation/Analysis: Solution turns yellow when a separate product is added, solid of the solution leaks down to the bottom after 20 minutes. Conclusion: The group tried to find the excess or limiting for the reaction between KI and Pb. In the end the hypothesis was supported by the data. We found that little amounts of each product led to a greater height of solids.
We waited 5 minutes for the respirometers to equilibrate after we measured the yeast solution in the graduated cylinder. I found that giving the conclusive data by recording the amount of milliliters in the pipette left after the 5 minutes were up. We had three trials all with 2.5% , 5% , 7.5% , and 10% solution. Limitations of Experimental Design Some possible reasons for error is the percentage of sucrose we contained in each trial of the experiment. This would affect the volume of gas captured in the pipette.
This, however, is not the case for adults. 3. Foot length (in inches) x 6.54 = Height (in inches) For my own height : 9 1/8 x 6.54 = 59.68 Height by formula = 59.68 inches Actual Height = 61.5 inches This is not a more accurate correlation between foot size and height because the difference is 1.82 inches, while the difference between my actual height and the height according to the graph was only 1.5 inches. 4. Based on my observations, someone’s height can be estimated by measuring the size of his or her shoe.
Research Question : What is the terminal velocity of a ball bearing in glycerin? Independent Variable: Distance travelled Dependent Variable : Time Controlled Variable(s): Height of Release Apparatus : * Glass Tube * Glycerin * Ball Bearings (3-4 mm in diameter, iron) * Clamps * Meter Stick * Stand * Iphone’s “Stopwatch app” Using a meter stick every 5 cm incresements were pointed out on to the side of the tube. Care was taken to start the measurements at the top level of glycerin, the bearing was released at the top of the tube. The time was measured by a group of Three people , one releasing the bearing ,second carefully observing the bearing as it fell through glycerin, third handling the stopwatch .Second person called out “lap” every time the bearing passed one of the 5 cm marks on the tube, after this call a person holding a stopwatch was supposed to obtain the split time between each of the 5 cm markers. The uncertainty in the distance is ±0.5 cm because the ruler had 1 cm markings.
Lastly we will explore standing waves and how string oscillations become affected by the string mass density. Theory As stated in order above, our first experiment of simple harmonic motion using an oscillating spring setup. By using a mass hanger attached to a rotary motion sensor, we are able to produce graphs and data to attempt to show the proofs for the theories and equations listed in the theory and graph section of the lab. The experiment started with adding 200g and progressively moved up to 350g for five trials. We then collected the data and analyzed the sine graph and the different portions of it and what they meant including the parameters and taking proper data.