484 Words2 Pages

Solving Proportions Using the Bear Population
Tiffany Platt
MAT 222
Roosevelt Davis
May 11, 2014
Solving Proportions Using the Bear Population Proportions are not only used in the math class but also in the real world. If you cook and follow recipes then they are being used on a daily basis especially if the recipe you’re using is designed for more or less people than your preparing the meal for. You have to figure out what to decrease or increase to make the meal suitable for you. Solving a proportion as learned in this week means that a number from an equation is missing and needs to be solved for. For this assignment I will be solving for the estimated: Bear population. To estimate the size of the bear population on the Keweenaw Peninsula, conservationists captured, tagged, and released 50 bears. One year later, a random sample of 100 bears included only 2 tagged bears. What is the conservationist's estimate of the size of the bear population? Problem 56 on page 437 Dugopolski M. (2012). The population size will be “x” and “x” needs to be solved for the equation will look like this 2/100=50/x. X = 100 the proportion is now set up and can be solved. I have to use cross
50 2 multiplication the extremes in this equation are x and 2. The means are 100 and 50.
2x=100(50) 2x=5000
2x = 5000 Both sides are divided by 2 2 2
X=2500, the bear population on Keweenaw Peninsula is estimated to be around 2500 bears. I have also been given a second problem in this assignment and y must be solved for in the equation. Also using proportions a single fraction also known as a ratio which exists on both sides of the equal sign which is a proportion that can be solved by cross multiplying the means and extremes. The given problem 10 on page 444, Dugopolski M. (2012).
4(y-1) = -3(x+3) after using cross multiplication
4y-4= -3x-9

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