3.) First, let’s find the slope from point A to point B. m=0-3/-3-0. This equals -3/-3, which reduces to positive 1. Now, we can use point-slope form. I will use point B and it would look like this: y-(0)=1(x-(-3)).
Write assignment statements that perform the following operations with the variables a, b, and c. a) Adds 2 to a and stores the result in b * b=a+2 b) Multiplier b times 4 and stores the result in a * a=b*4 c) Divides a by 3.14 and stores the result in b * b=a/3.14 d) Subtract 8 from b and stores the result in a * a=b-8 4. Assume the variables result, w, x, y, and z are all integers, and that w=5, x=4, y=8, and z=2. What value will be stored in result in each of the following statements? a) Set result = x + y * 12= x + y b) Set result = z + 2 * 4=z * 2 c) Set result = y / x * 2=y / x d) Set result =y – z * b=y – z 5. Write a pseudocode statement that declares the variable cost so it can hold real numbers.
Find the inverse of 13. Solve 14. Find the determinant by using expansion of signed minors of the first row : 15. Given the augmented matrix ,use row operations to obtain a zero in the second row, first column. 16.
| The legs have length '24' and 'X' are the legs. The hypotenuse is 26. See Picture | The hypotenuse is red in the diagram below: Step 2) Substitute values into the formula (remember 'c' is the hypotenuse) | A2 + B2 = C2 x2 + 242 = 262 | Step 3) Solve for the unknown | | Problem 1) Find the length of X | | Step 1 | Remember our steps for how to use this theorem. This problems is like example 1 because we are solving for the hypotenuse . Step 1) Identify the legs and the hypotenuse of the right triangle.
Planck's constant: the constant relating the change in energy for a system to the frequency of the electromagnatic radiation absorbed or emitted, equal to 6.626 X 10^-34 J 5. Quantization: the concept that energy can occur only in discrete units called quanta 6. Photon: a quantum of electromagnetic radiation 7. Photoelectric effect: ejection of electrons from a substance by incident electromagnetic radiation, especially by visible light 8. E=mc^2: Einstein's equation proposing that energy has mass; E is energy, m is mass, and c is the speed of light 9.
What is x? The Pythagorean Theorem states that in every right triangle with legs the length a and b and hypotenuse c, these lengths have the relationship of a2 + b2=c2. a=x b=(2x+4)2 c=(2x+6)2 this is the binomials we will insert into our equation x2+(2x+4)2=(2x+6)2 the binomials into the Pythagorean Theorem x2+4x2+16x+16=24x36 the binomial squared. The 4x2can be subtracted out first x2+16x+16=24x+36 now subtract 24x from both sides x2+-8x+16=36 now subtract 36 from both sides x2-8x-20=0 this is a quadratic equation to solve by factoring and using the zero factor. (x- )(x+ ) the coefficient of x2 is one (1).
P(1+r/2)(1+r/2) Next step is to multiply the squared quantity. P(1+(r/2)+(r/2)+(r2/4)) Then carry out FOIL. P(1+(2r/2)+(r2/4)) Combine like terms. P+(2Pr/2)+(Pr2/4) Distribute P throughout the trinomial 4P+4Pr+Pr2 Simplified. 4 Now, unlike traditional polynomials, the one used above is not in descending order of the variables.
Begin by writing the corresponding linear equations, and then use back-substitution to solve your variables. 10–1301–8001 159–1 x,y,z=( , , ) 10–1301–8001 159–1 = x-13z=15y-8z=9z=-1 = x-13(-1)=15y-8(-1)=9z=-1 = x=2y=1z=-1 x,y,z=(2 , 1 , -1) Determinants and Cramer’s Rule: 2. Find the determinant of the given matrix. 8–2–12 8–2–12 = 8*2 - (-1)(-2) = 16 - 2 = 14 3. Solve the given linear system using Cramer’s rule.
What is the median of the above values? The median is calculated by adding together the two middle numbers and dividing by 2 (2 values). The numbers must be in ascending or descending order. 5.0+5.7=10.7/2=5.35=5.4 is the median of the numbers listed in this question. What is the mean of the above values?
Student designed practical investigation Title: Atwood’s Machine (Newtons 2nd law of motion). Partner: Qurban Aim: To explore how two different masses act with each other on a pulley and therefore calculate acceleration a (theoretical and experimental) and the Tension T. Hypothesis: When both masses are the same, there should be no acceleration. The larger the ratio between one mass and the other, the higher the acceleration should be. Materials: Pulley, string, mass 1 + 2, ruler, stopwatch, scissors Apparatus: Theory: Since we are trying to find a, the equations we need are: For experimental a: Transposed to: Theoretical a: For tension: where x = displacement u = initial velocity t = time taken = mass 1 = mass 2 Let Method: 1. Set up the apparatus in the diagram above.